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3 years ago

What kind of chemical reaction does the chemical equation sodium + chlorine → sodium chloride represent?

Chemistry

2 answers:

Rzqust [24]3 years ago

4 0

I belive its A, Combustion

Marizza181 [45]3 years ago

4 0

Thr answer would be D. Synthesis.

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Write the Lewis structure for the product that forms when boron trifluoride combines with ammonia. Remember to show all non-zero

horrorfan [7]

Answer:

To draw or sketch a Lewis structure, formula or diagram, the chemical formula of the compound is essential. Without it you can not even know what are the atoms that make it up, in our case it is the one observed in the reaction shown:

$BF_{3}$ + $:NH_{3}$ ⇒ F3 $F_{3} BNH_{3}$

In the structure obtained (see the Lewis structure in the drawing) the black dots correspond to the electrons of the non-shared pairs. Because hydrogen has a single electron and a single orbital available to fill, it forms only a covalent bond represented by a long dash. The same goes for boron and fluorine but in this case the fluorine has pairs of free electrons.

Explanation:

Lewis's structure is all that representation of covalent bonds within a molecule or an ion. In it, said bonds and electrons are represented by long dots or dashes, although most of the times the dots correspond to non-shared electrons and dashes to covalent bonds.

All existing compounds can be represented by Lewis structures, giving a first approximation of how the molecule or ions could be.

8 0

3 years ago

25.0cm3 of s saturated potassium hydroxide is neutralized by 35.0cm3 of hydrogen chloride acid of concentration 0.75 mol/dm3. Ca

Kamila [148]

Answer:

Concentration of the original $\rm KOH$ solution: approximately $1.05\; \rm mol \cdot dm^{-3}$ .

Explanation:

Notice that the concentration of the $\rm HCl$ solution is in the unit $\rm mol\cdot dm^{-3}$ . However, the unit of the two volumes is $\rm cm^{3}$ . Convert the unit of the two volumes to $\rm dm^{3}$ to match the unit of concentration.

$\begin{aligned} V(\mathrm{NaOH}) &= 25.0\; \rm cm^{3} \\ &= 25.0\; \rm cm^{3} \times \frac{1\; \rm dm^{3}}{1000\; \rm cm^{3}} \approx 0.0250\; \rm dm^{3} \end{aligned}$ .

$\begin{aligned} V(\mathrm{HCl}) &= 35.0\; \rm cm^{3} \\ &= 35.0\; \rm cm^{3} \times \frac{1\; \rm dm^{3}}{1000\; \rm cm^{3}} \approx 0.0350\; \rm dm^{3} \end{aligned}$ .

Calculate the number of moles of $\rm HCl$ molecules in that $0.0350\; \rm dm^{3}$ of $0.75\; \rm mol \cdot dm^{3}$ $\rm HCl\!$ solution:

$\begin{aligned}n(\mathrm{HCl}) &= c(\mathrm{HCl}) \cdot V(\mathrm{HCl}) \\ &= 0.00350\; \rm dm^{3} \times 0.75\; \rm mol \cdot dm^{3} \\ &\approx 0.02625\; \rm mol\end{aligned}$ .

$\rm HCl$ is a monoprotic acid. In other words, each $\rm HCl\!$ would release up to one proton $\rm H^{+}$ .

On the other hand, $\rm KOH$ is a monoprotic base. Each $\rm KOH\!$ formula unit would react with up to one $\rm H^{+}$ .

Hence, $\rm HCl$ molecules and $\rm KOH\!$ formula units would react at a one-to-one ratio.

${\rm HCl}\, (aq) + {\rm NaOH}\, (aq) \to {\rm NaCl}\, (aq) + {\rm H_2O}\, (l)$ .

Therefore, that $0.02625\; \rm mol$ of $\rm HCl$ molecules would neutralize exactly the same number of $\rm NaOH$ formula units. That is: $n(\mathrm{NaOH}) = 0.02625\; \rm mol$ .

Calculate the concentration of a $\rm NaOH$ solution where $V(\mathrm{NaOH}) = 0.0250\; \rm dm^{3}$ and $n(\mathrm{NaOH}) = 0.02625\; \rm mol$ :

$\begin{aligned}c(\mathrm{NaOH}) &= \frac{n(\mathrm{NaOH})}{V(\mathrm{NaOH})} \\ &= \frac{0.02625\; \rm mol}{0.0250\; \rm dm^{3}}\approx 1.05\; \rm mol \cdot dm^{-3}\end{aligned}$ .

7 0

3 years ago

Calculate ΔGrxn for this equation, rounding your answer to the nearest whole number. CaCO3(s) → CaO(s) + CO2(g) ΔGf,CaCO3 = −1,1

FrozenT [24]

Answer: $\Delta G_{rxn}$ for the given reaction is 130.19kJ/mol

Explanation:

To Calculate the $\Delta G_{rxn}$ , we use the formula:

$\Delta G_{rxn}=\Delta G_{products}-\Delta G_{reactants}$

For the given chemical reaction:

$CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

We are given:

$\Delta G_{CaCO_3}=-1128.76kJ/mol\\\Delta G_{CaO}=-604.17kJ/mol\\\Delta G_{CO_2}=-394.4kJ/mol$

Now, to calculate $\Delta G_{rxn}$ , we put the values in the above equation:

$\Delta G_{rxn}=(\Delta G_{CaO}+\Delta G_{CO_2})-\Delta G_{CaCO_3}$

$\Delta G_{reaction}=(-604.17-394.4)-(-1128.76)kJ/mol\\\Delta G_{reaction}=130.19kJ/mol$

As, the value of $\Delta G_{reaction}$ comes out to be positive, the reaction is said to be non-spontaneous reaction.

3 0

3 years ago

Which are the correct statements (image)

liq [111]

Answer:

Explanation:

3 0

4 years ago

The valency of chlorine is.<br><br>what does it mean<br>

Papessa [141]

Answer:

Explanation:

The valency of chlorine is 1 .It means that chlorine has seven valence electrons in its valence shell so it gains one electron from others to be stable during chemical reaction. so its valency is 1.

hope it helps :)

5 0

3 years ago