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tino4ka555 [31]
3 years ago
5

Consider two copper wires of equal cross-sectional area. One wire has 3 times the length of the other. How do the resistivities

of these two wires compare? Consider two copper wires of equal cross-sectional area. One wire has 3 times the length of the other. How do the resistivities of these two wires compare? The longer wire has 3 times the resistivity of the shorter wire. The longer wire has 27 times times the resistivity of the shorter wire. The longer wire has 9 times times the resistivity of the shorter wire. Both wires have the same resistivity.
Physics
1 answer:
vladimir2022 [97]3 years ago
7 0

Answer:

Both wires have the same resistivity.

Explanation:

The resistivity of a material depends on the following factors:

  1. The nature of the material, i.e., the number density of free electrons of the material.
  2. The temperature of the material.

The resistance R of a wire of resistivity \rho, length l and cross-sectional area A is given by

R=\dfrac{\rho l}{A}.

On varying the length and cross-sectional area of the wire, the resistance of the wire is changed but resistivity does not change as it is an intrinsic property of the material of the wire.

For the two given wires, the length and the cross-sectional area are different, but both the wires are of copper which means the number density of free electrons on both the wires is same and both the wires are placed in same environmental condition, which means the temperature would also be same.

Thus, the resistivities of both the wire are same.

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meriva

Answer:

The initial velocity of the softball is 14.711 meters per second.

Explanation:

This is a case of an object which experiments a free fall, that is, an uniform accelerated motion due to gravity and in which effects from air friction and Earth's rotation can be neglected.

From statement we must understand that the student threw the softball upwards and it is caught at original position 3.56 seconds later. Initial and final heights, time and gravitational acceleration are known and initial speed is unknown. The following equation of motion is used:

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Where:

y_{o} - Initial height of the softball, measured in meters.

y - Final height of the softball, measured in meters.

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g - Gravitational acceleration, measured in meters per square second.

If we know that y = y_{o}, t = 3.56\,s and g = -9.807\,\frac{m}{s^{2}}, the initial velocity of the softball is:

v_{o}\cdot (3\,s)+\frac{1}{2}\cdot (-9.807\,\frac{m}{s^{2}} )\cdot (3\,s)^{2} = 0

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The initial velocity of the softball is 14.711 meters per second.

8 0
3 years ago
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