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Tamiku [17]
3 years ago
11

How much energy in joules does a photon with a frequency of 6.89 x 10

Chemistry
1 answer:
xxMikexx [17]3 years ago
8 0

689

Explanation:

Ritz thks t too okay if appeal type topic topic egg Enzo team 6 users Elba room

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Identify the intermediate leads to the major product for the reaction of 2-methyl-2-butene with hydrogen bromide in the presence
pishuonlain [190]

Answer:

II

Explanation:

We must have a good idea of the fact that there are two mechanisms that come into play when we are discussing about the addition of hydrogen halides to alkenes. The first is the ionic mechanism and the second is the radical mechanism.

The ionic mechanism is accounted for by the Markovnikov rule while the radical mechanism occurs in the presence of peroxides and is generally referred to as anti Markovnikov  addition.

The intermediate in anti Markovnikov  addition involves the most stable radical, in this case, it is a tertiary radical as shown in the images attached. The most stable radical is II hence it leads to the major product shown in the other image.

4 0
3 years ago
The compound Fe3CI is made of what?
sergeinik [125]

Answer:

nglos324 - fe3c. Iron carbide is an interstitial compound of iron and carbon with the composition Fe- 6.68 wt % Carbon. It is a brittle ceramic material and is produced in carbon steels or cast irons during pseudo-equilibrium cooling from above the eutectoid temperature (723 C).

Explanation:

4 0
3 years ago
Why is a terminal alkyne favored when sodium amide (NaNH2) is used in an elimination reaction with 2,3-dichlorohexane
mihalych1998 [28]

The question is incomplete, the complete question is;

Why is a terminal alkyne favored when sodium amide (NaNH2) is used in an elimination reaction with 2,3-dichlorohexane? product. A) The terminal alkyne is more stable than the internal alkyne and is naturally the favored B) The terminal alkyne is not favored in this reaction. C) The resonance favors the formation of the terminal rather than internal alkyne. D) The strong base deprotonates the terminal alkyne and removes it from the equilibrium.

E) The positions of the Cl atoms induce the net formation of the terminal alkyne.

Answer:

E) The positions of the Cl atoms induce the net formation of the terminal alkyne.

Explanation:

In this reaction, sterric hindrance plays a very important role. We know that sodamide is a strong base, it tends to attack at the most accessible position.

The first deprotonation yields an alkene. The strong base attacks at the terminal position again and yields the terminal alkyne. Thus the structure of the dihalide makes the terminal hydrogen atoms most accessible to the base. Hence the answer.

7 0
3 years ago
The equilibrium constant, k, for a redox reaction at 25° c is 7.3 × 107. what is the value of e° if the overall reaction transfe
Novay_Z [31]

Answer:

0.23 V.

Explanation:

<em>∵ ΔG° = -RT lnK.</em>

∴ ΔG° = -RTlnK = -(8.314 J/mol)(298 K) ln(7.3 × 10⁷) = - 44.86 x 10³ J/mol.

<em>∵ ΔG° = - nFE°</em>

∴ E° = - ΔG°/nF = - (- 44.86 x 10³ J/mol)/(2 x 96500 s.A/mol) = 0.2324 V ≅ 0.23 V.

5 0
3 years ago
Write a balanced half-reaction describing the reduction of aqueous iron(III) cations to aqueous iron(II) cations.​
melamori03 [73]

Answer:

The answer to your question is:

Explanation:

                  Iron (III)  ⇒ Iron (II)

                  Fe⁺³ + 1e⁻   ⇒   Fe⁺²

                 

6 0
3 years ago
Read 2 more answers
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