1. Which of the following is a typical characteristic of ionic solids?

How many milliliters of a 3.4 M NaCl solution would be needed to prepare each solution?

Ksenya-84 [330]

Answer:

a. Approximately $1.3\; \rm mL$ .

b. Approximately $7.2\; \rm mL$ .

Explanation:

The unit of concentration " $\rm M$ " is equivalent to " $\rm mol \cdot L^{-1}$ ", which means "moles per liter."

However, the volume of both solutions were given in mililiters $\rm mL$ . Convert these volumes to liters:

$\displaystyle 45\; \rm mL = 45\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.045\; \rm L$ .

$\displaystyle 330\; \rm mL = 330\; \rm mL \times \frac{1\; \rm L}{1000\; \rm mL} = 0.330\; \rm L$ .

In a solution of volume $V$ where the concentration of a solute is $c$ , there would be $c \cdot V$ (moles of) formula units of this solute.

Calculate the number of moles of $\rm NaCl$ formula units in each of the two solutions:

Solution in a.:

$n = c \cdot V = 0.045\; \rm L \times 0.10\; \rm mol \cdot L^{-1} = 0.0045\; \rm mol$ .

Solution in b.:

$n = c \cdot V = 0.330\; \rm L \times 0.074\; \rm mol \cdot L^{-1} = 0.02442\; \rm mol$ .

What volume of that $3.4\; \rm M$ (same as $3.4 \; \rm mol \cdot L^{-1}$ ) $\rm NaCl$ solution would contain that many

For the solution in a.:

$\displaystyle V = \frac{n}{c} = \frac{0.0045\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0013\; \rm L$ .

Convert the unit of that volume to milliliters:

$\displaystyle 0.0013\; \rm L = 0.0013\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 1.3\; \rm mL$ .

Similarly, for the solution in b.:

$\displaystyle V = \frac{n}{c} = \frac{0.02442\; \rm mol}{3.4\; \rm mol \cdot L^{-1}} \approx 0.0072\; \rm L$ .

Convert the unit of that volume to milliliters:

$\displaystyle 0.0072\; \rm L = 0.0072\; \rm L \times \frac{1000\; \rm mL}{1\; \rm L} = 7.2\; \rm mL$ .

8 0

3 years ago

Which statement is true about the radii of Na and Na+?

kicyunya [14]

Answer:

Na has a larger atomic radius than Na+.

Explanation:

5 0

2 years ago

The diagram shows different forms of thermal energy transfer.

omeli [17]

A. conduction
that is the correct answer

6 0

3 years ago

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A mixture of He , Ar , and Xe has a total pressure of 3.00 atm . The partial pressure of He is 0.200 atm , and the partial press

yaroslaw [1]

The partial pressure of Xe is 2.60atm

The sum of the partial pressures is equal to the total pressure. Ptotal = P1 + P2 + P3... .To calculate the partial pressure of one of the components of a mixture, subtract the sum of known partial pressures of the other components from the total pressure.

Given the values of

PHe=0.20 atm

PAr=0.20 atm

Ptotal=3.00 atm

We need to find PXe

Solution: Determine the sum of the partial pressures of helium and argon, then subtract the sum from the total pressure.

PHe+PAr =0.20 atm + 0.20=0.400 atm

PXe=3.00atm−0.400=2.60 atm

Each gas that makes up a mixture of gases has a partial pressure, which is the notional pressure of that gas as if it alone filled the original combination's complete volume at the same temperature.

According to Dalton's Law, a perfect gas mixture's total pressure equals the sum of its constituent gases' individual partial pressures.

The thermodynamic activity of a gas's molecules is gauged by its partial pressure.

Gases react, disperse, and dissolve based on their partial pressures rather than the concentrations they have in liquids or other gas combinations.

This general characteristic of gases holds true in biological chemical interactions involving gases.

Hence the partial pressure of Xe is 2.60atm

Learn more about partial pressure here

brainly.com/question/19813237

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5 0

2 years ago

Brainliets and a lot of points to ever answers all questions and get all right

Juli2301 [7.4K]

Answer:

try at your own

4 0

3 years ago

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