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grigory [225]
3 years ago
14

How many molecules of dinitrogen pentoxide are in 0.27 moles of dinitrogenpentoxide?​

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
4 0

Answer:

1.6 × 10²³ molecules of N2O5

Explanation:

To find the amount of molecules from the amount of moles of a substance we simply multiply the amount of moles by Avagadro's number.

0.27mol × 6.02×10²³ = 1.6 × 10²³ molecules of N2O5

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igor_vitrenko [27]

Answer:

I think A should be the answer because oxygen is the chemical change of carbon.

7 0
3 years ago
A 150 mL of oxygen gas is collected over water at 20 °C and 758 torr. What volume will the same sample of oxygen occupy at STP w
Stella [2.4K]

Answer:

The volume would be; 136.17 ml

Explanation:

Volume V1 = 150 mL

Temperature T1 = 20°C + 273 = 293 K

Pressure  P1 = 758 - 17.54 = 740.46 torr

At STP;

Volume V2 = ?

Pressure P2 = 760 torr

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Using the general gas equation;

P1V1 / T1   = P2V2 / T2

Making V2 subject of formulae;

V2 = P1V1T2 / T1P2

Inserting the values we have;

V2 = 740.46 * 150 * 273  /  293 * 760

V2 = 136.17 ml

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3 years ago
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IrinaK [193]
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