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grigory [225]
3 years ago
14

How many molecules of dinitrogen pentoxide are in 0.27 moles of dinitrogenpentoxide?​

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
4 0

Answer:

1.6 × 10²³ molecules of N2O5

Explanation:

To find the amount of molecules from the amount of moles of a substance we simply multiply the amount of moles by Avagadro's number.

0.27mol × 6.02×10²³ = 1.6 × 10²³ molecules of N2O5

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Draw the products of the transformation shown by the fishhook notation. Include any electrons.
andrew11 [14]

Answer:

Explanation:

The question is based on the concept of the cleavage of bonds. In the process of the reaction the breaking of bonds is required. The cleavage of the bonds make the bonded electrons free to involve in the reaction process.

Fundamentals:

The cleavage of the bond can be done in two ways: homolytic or heterolytic. The heterolytic cleavage occurs when the shared electrons of the covalent bond are taken away by either of the atom. The heterolytic cleavage results in generation of the charged molecules. On the other hand, the homolytic cleavage is the cleavage in which the shared pair of the electrons are equally distributed, resulting in generation of free radicals.

4 0
3 years ago
For a given sample of ch3oh, the enthalpy change during the reaction is 82.3 kj . how many grams of methane gas are produced?
Leno4ka [110]
The equation is as follows;
 2CH3OH(g) = 2CH4(g) + O2(g), ΔH= +252.8 kJ
From the equation; for the reaction to produce 2 moles of methane (32g) an energy of 252.8 kJ is released.
Therefore; for an energy of 82.3 kJ the number of moles that will be produced will be;    =  (2×82.3)/252.3
                               = 0.6524 moles
                  which is equivalent to 0.6524 × 16 = 10.438 g
There, the mass of CH4 produced will be 10.438 g


8 0
4 years ago
What is the freezing point (in degrees Celcius) of 3.75 kg of water if it contains 189.9 g of C a B r 2?
blondinia [14]

Answer:

The freezing point of the solution is -1.4°C

Explanation:

Freezing point decreases by the addition of a solute to the original solvent, <em>freezing point depression formula is:</em>

ΔT = kf×m×i

<em>Where Kf is freezing point depression constant of the solvent (1.86°C/m), m is molality of the solution (Moles CaBr₂ -solute- / kg water -solvent) and i is Van't Hoff factor.</em>

Molality of the solution is:

-moles CaBr₂ (Molar mass:

189.9g ₓ (1mol / 199.89g) = 0.95 moles

Molality is:

0.95 moles CaBr₂ / 3.75kg water = <em>0.253m</em>

Van't hoff factor represents how many moles of solute are produced after the dissolution of 1 mole of solid solute, for CaBr₂:

CaBr₂(s) → Ca²⁺ + 2Br⁻

3 moles of ions are formed from 1 mole of solid solute, Van't Hoff factor is 3.

Replacing:

ΔT = kf×m×i

ΔT = 1.86°C/m×0.253m×3

ΔT = 1.4°C

The freezing point of water decreases in 1.4°C. As freezing point of water is 0°C,

<h3>The freezing point of the solution is -1.4°C</h3>

<em />

4 0
3 years ago
Read 2 more answers
A well-known scientist testifies that she believes a piece of evidence is accepted by science. The judge rules that the evidence
notsponge [240]

Answer:

The correct answer is C:

Kumho Tire Co. Ltd V. Daubert

Explanation:

In this case, the appellant (Daubert) has sued Kumho Tire Co. Ltd (the defendant) when 3 months prior the right rear tyre of his car exploded while the car was in motion killing a passenger and injuring others severely.

The appellant employed the services of an expert who had worked for 10 years with Michelin to give his opinion as having studied the attributes of the tire technology.  

In a counter-argument, the defendant rather than dispute the opinion of the expert urged the court to exclude it as evidence because his methodology didn't conform to the requirements of the Law as given in Rule 702 of the Federal Rules of Evidence.

True to the defendants' position, the Law by the ruling in Daubert v Merrell Dow Pharmaceuticals required that for the opinion to count, it had to be scientifically correct. It was hence excluded as evidence in the case.

Cheers!

5 0
4 years ago
If 20.00 moles of KClO3 react, how many molecules of O2 will form?
Tanzania [10]

Answer:

Explanation:

2KClO₃ = 2KCl + 3O₂

2 moles of potassium chlorate gives 3 moles of oxygen gas

20 moles of potassium chlorate will give 30  moles of oxygen gas .

30 moles of oxygen = 30 x 6.02 x 10²³ molecules of oxygen .

= 180.6 x 10²³ molecules of O₂ .

6 0
3 years ago
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