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krok68 [10]
3 years ago
14

A 988ml sample of air is at 852 mm Hg and 34.1 C. What will the temperature of this gas be, in Fahrenheit, at 955 mm Hg and a vo

lume of 602 mL
Chemistry
1 answer:
prohojiy [21]3 years ago
4 0

Answer:

T₂ = 63.78  °F

Explanation:

Given data:

Initial Volume = 988 mL

Initial Pressure = 852 mmHg

Initial temperature = 34.1 °C

Final pressure = 955 mmHg

Final volume = 602 mL

Final temperature = ?

Solution:

(34.1 °C × 9/5) +32  = 93.38 °F

Formula:

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

T₂  = P₂V₂T₁/P₁V₁

T₂ = 955 mmHg ×  602 mL × 93.38 °F / 852 mmHg× 988mL.

T₂ = 53685095.8 °F /841776

T₂ = 63.78  °F

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Crank

Answer:

Option D. Al is above H on the activity series.

Explanation:

The equation for the reaction is given below:

2Al + 6HBr —> 2AlBr₃ + 3H₂

The activity series gives us a background understanding of the reactivity of elements i.e how elements displace other elements when present in solution.

From the activity series of metals, we understood that metal higher in the series will displace those lower in the series.

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4 0
3 years ago
Collected data consists of:
san4es73 [151]

The number of moles of the magnesium (mg) is 0.00067 mol.

The number of moles of hydrogen gas is 0.0008 mol.

The volume of 1 more hydrogen gas (mL) at STP is 22.4 L.

<h3>Number of moles of the magnesium (mg)</h3>

The number of moles of the magnesium (mg) is calculated as follows;

number of moles = reacting mass / molar mass

molar mass of magnesium (mg) = 24 g/mol

number of moles = 0.016 g / 24 g/mol = 0.00067 mol.

<h3>Number of moles of hydrogen gas</h3>

PV = nRT

n = PV/RT

Apply Boyle's law to determine the change in volume.

P1V1 = P2V2

V2 = (P1V1)/P2

V2 = (101.39 x 146)/(116.54)

V2 = 127.02 mL

Now determine the number of moles using the following value of ideal constant.

R = 8.314 LkPa/mol.K

n = (15.15 kPa x 0.127 L)/(8.314 x 290.95)

n = 0.0008

<h3>Volume of 1 mole of hydrogen gas at STP</h3>

V = nRT/P

V = (1 x 8.314 x 273) / (101.325)

V = 22.4 L

Learn more about number of moles here: brainly.com/question/13314627

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