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Minchanka [31]
3 years ago
14

#1. Which of the following is a reasonable ground-state electron configuration? A.-1s21p62s22p63s2/ B. -1s22s22p63s23p64s24d8/ C

. -1s22s22p63p6/D. -1s22s22p63s1 #2. Which of the following is a possible noble gas notation? A.-[Xe] 6s26p6/B. -[Kr] 5s25d85p6 /C.-[Xe] 6s25d106p4/D. -[Kr] 5s24d105p3
Chemistry
2 answers:
Sladkaya [172]3 years ago
6 0
A ground state electron configuration follows the Aufbau Principle that states that electrons should be filled up in orbitals in increasing energy. In the given sequences, the right configuration is <span>1s2 2s2 2p6 3s2 3p6 4s2 3d8. The choice that conforms to this sequence is D. In 2) the possible confirmation that follows Aufbau's principle is D. </span>
nadezda [96]3 years ago
6 0

Answer:

1) D. -1s2 2s2 2p6 3s1: It is reasonable configuration.

2) [Xe] 6s2 6p6:

Explanation:

A.-1s2 1p6 2s2 2p6 3s2: it is not possible as first shell has only one subshell which is "s". 1p does not exist.

B. -1s2 2s2 2p6 3s2 3p6 4s2 4d8: not possible as first 3d orbital will be filled followed by 4p.

C. -1s2 2s2 2p6 3p6:It is not possible as first 3s orbital will be filled than 3p6.

D. -1s2 2s2 2p6 3s1: It is reasonable configuration.

2)  

A.-[Xe] 6s2 6p6: completely filled so it cannot be noble gas configuration

B. -[Kr] 5s2 5d8 5p6 : Partial filled so it cannot be noble gas configuration

C.-[Xe] 6s2 5d10 6p4: Partial filled so it cannot be noble gas configuration

D. -[Kr] 5s2 4d10 5p3:Partial filled so it cannot be noble gas configuration

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The final temperature in Celsius of the metal block is 49°C.

<h3>How to find the number of moles ?</h3>

Moles water = \frac{\text{Given mass}}{\text{Molar Mass}}

                     = \frac{0.48\ g}{18\ \text{g/mol}}

                     = 0.0266 moles  

                   

Heat lost by water = 0.0266 mol x 44.0 kJ/mol

                                = 1.17 kJ

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Heat lost = Heat gained

Heat gained by aluminum = 1170 J  

1170 = 55 x 0.903 (T - 25) = 49.7 T - 1242  

1170 + 1242 = 49.7 T  

T = 48.5°C (49°C at two significant figures)

Thus from the above conclusion we can say that The final temperature in Celsius of the metal block is 49°C.

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What is a neutralisation reaction? Give two examples.
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= -0.0547\times 11018

= -602.69 \ KJ \ heat

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