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Minchanka [31]
3 years ago
14

#1. Which of the following is a reasonable ground-state electron configuration? A.-1s21p62s22p63s2/ B. -1s22s22p63s23p64s24d8/ C

. -1s22s22p63p6/D. -1s22s22p63s1 #2. Which of the following is a possible noble gas notation? A.-[Xe] 6s26p6/B. -[Kr] 5s25d85p6 /C.-[Xe] 6s25d106p4/D. -[Kr] 5s24d105p3
Chemistry
2 answers:
Sladkaya [172]3 years ago
6 0
A ground state electron configuration follows the Aufbau Principle that states that electrons should be filled up in orbitals in increasing energy. In the given sequences, the right configuration is <span>1s2 2s2 2p6 3s2 3p6 4s2 3d8. The choice that conforms to this sequence is D. In 2) the possible confirmation that follows Aufbau's principle is D. </span>
nadezda [96]3 years ago
6 0

Answer:

1) D. -1s2 2s2 2p6 3s1: It is reasonable configuration.

2) [Xe] 6s2 6p6:

Explanation:

A.-1s2 1p6 2s2 2p6 3s2: it is not possible as first shell has only one subshell which is "s". 1p does not exist.

B. -1s2 2s2 2p6 3s2 3p6 4s2 4d8: not possible as first 3d orbital will be filled followed by 4p.

C. -1s2 2s2 2p6 3p6:It is not possible as first 3s orbital will be filled than 3p6.

D. -1s2 2s2 2p6 3s1: It is reasonable configuration.

2)  

A.-[Xe] 6s2 6p6: completely filled so it cannot be noble gas configuration

B. -[Kr] 5s2 5d8 5p6 : Partial filled so it cannot be noble gas configuration

C.-[Xe] 6s2 5d10 6p4: Partial filled so it cannot be noble gas configuration

D. -[Kr] 5s2 4d10 5p3:Partial filled so it cannot be noble gas configuration

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Pls help
Irina-Kira [14]

Answer:

CrO₂ --------------------> Cr⁴⁺ and O²⁻

VCO₃ -------------------> V²⁺ and CO₃²⁻

Cr₂(SO₄)₃ -------------> Cr³⁺ and SO₄²⁻

(NH₄)₂S ----------------> NH₄⁺ and S²⁻

Explanation:

Within ionic compounds, the cation is listed first, followed by the anion. Some of the ions are polyatomic, meaning they are covalently bonded to other elements. Polyatomic ions always have a specific charge.

All of these ionic compounds have an overall charge of 0. As such, the charges of the cations and anions must balance out. In order to do so, there are some compounds which have more than one atom of each ion.

2.) CrO₂

------> Oxygen (O) always forms the anion, O²⁻.

------> Therefore, if there are 2 oxygen anions, the chromium (Cr) must have the cationic form of Cr⁴⁺.

------> +4 + (-2) + (-2) = 0

3.) VCO₃

------> Carbonate (CO₃), a polyatomic ion, always has the state CO₃²⁻.

------> If there is only one atom of each ion, the charges must perfectly balance, making vanadium (V) be the cation V²⁺.

------> +2 + (-2) = 0

4.) Cr₂(SO₄)₃

------> Sulfate (SO₄), a polyatomic ion, always has the state SO₄²⁻.

-------> The only way the charges could balance out is if the chromium (Cr) is in the cationic form Cr³⁺.

------> +3 + 3 + (-2) + (-2) + (-2) = 0

5.) (NH₄)₂S

------> Ammonium (NH₄), a polyatomic ion, always has the state NH₄⁺.

------> Sulfur (S) always forms the anion S²⁻.

------> +1 + 1 + (-2) = 0

3 0
2 years ago
What types of intermolecular forces are found in CH<br> 4
Sphinxa [80]
London dispersion forces
8 0
3 years ago
Show me step by step solution
Cloud [144]
Ok I may be young but combine the two reactions to create a compund
7 0
3 years ago
What quantity is measured in mol/dm³?
natima [27]
L
M =  \frac{n}{V}  \\ M = \frac{mol}{L}  \\ or \\ M =  \frac{mol}{ {dm}^{3} }
mol/dm³ is measure for molarity
3 0
3 years ago
Tin(ii) fluoride (snf2) is often added to toothpaste as an ingredient to prevent tooth decay. what is the mass of f in grams in
a_sh-v [17]
From the periodic table:
molar mass of Sn = 118.71 grams
molar mass of F = 18.99 grams

This means that:
molar mass of SnF2 = 118.71 + 2(18.99) = 156.69 grams

Therefore, 156.69 grams of SnF2 contains 37.98 grams of F. To know the amount of F in 36.5 grams of the compound, we will simply do a cross multiplication as follows:
mass of F = (36.6 x 37.98) / 156.69 = 8.847 grams
3 0
3 years ago
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