Answer:
the speed of the car moving after accelerating for 56 m is 20 m/s
Explanation:
The computation is shown below:
As we know that
Vf^2 = Vi^2 + 2ad
= ( 8m/s )^2 + 2 ( 3m/s2 ) ( 56m)
= 400 m2/s2
Vf = 20 m/s
Hence, the speed of the car moving after accelerating for 56 m is 20 m/s
"Gravity gets stronger when there's more mass and weaker when you get farther away" tells you very little.
"A whole lot of energy can come from just a little tiny bit of mass" tells you very little.
And "The speed of light is very very very very very fast" tells you almost nothing.
Explanation:
The question is incomplete. Here is the complete question.
<em>A toy rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward acceleration during the burn phase. At the instant of engine burnout, the rocket has risen to 98 m and acquired a velocity of 30m/s. The rocket continues to rise in unpowered flight, reaches maximum height, and falls back to the ground. The upward acceleration of the rocket during the burn phase is closest to...</em>
<em></em>
Given
initial velocity of rocket u = 0m/s
final velocity of rocket = 30m/s
Height reached by the rocket = 98m
Required
<em>upward acceleration of the rocket </em>
<em></em>
<em>Using the equation of motion below to get the acceleration a:</em>
<em></em><em></em>
<em></em>
<em>Hence upward acceleration of the rocket during the burn phase is closest to 5m/s²</em>
<em />
<em>Note that the velocity used in calculation was assumed.</em>
True
Explanation: impervious surfaces are any materials that do not allow water to flow through them such a concrete and asphalt
Answer:
81313.81313.13131
Explanation
find volume 22/7 ×0.03×0.03=0.002828571 × 0.003= 0.000008485
0.69÷0.000008485