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Mice21 [21]
3 years ago
15

Rank the measurements in order of increasing pressure.

Physics
2 answers:
sweet-ann [11.9K]3 years ago
7 0
<span>For the answer to the question above.
The pressure (the symbol "P") is the force per unit area applied in a direction perpendicular to the surface of an object.
This is from least to greatest: 0.3Pa, 16 N/m2, 311 N.m2, 4kPa</span>
MrRa [10]3 years ago
3 0

Answer : The correct option is, (0.3Pa),(16N/m^2),(311N/m^2),(4KPa)

Explanation :

As we know that,

1atm=101325\frac{N}{m^2}\\\\(1\frac{N}{m^2}=1Pa)\\\\101325\frac{N}{m^2}=101325Pa\\\\(1KPa=1000Pa)\\\\101325Pa=101.325KPa

Now we convert all the given values of the pressure into the Pascal(Pa), we get

4KPa=4\times 1000Pa=4000Pa\\\\16\frac{N}{m^2}=16Pa\\\\311\frac{N}{m^2}=311Pa

Thus, the measurements in order of increasing pressure is,

(0.3Pa)


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you are piloting a small plane and you want to reach an airport 450 km due south in 3.0 h a wind is blowing from the west 50.0 k
alex41 [277]

Answer:

You should choose airspeed 158.11 km/h at 18.4° west of south

Explanation:

The distance to the air port is 450 km due to south

You should to reach the airport in 3 hours

→ Velocity = distance ÷ time

→ Distance = 450 km , time = 3 hours

→ The velocity of your plane = 450 ÷ 3 = 150 km/h due to south

A wind is blowing from west 50 km/h

We need to know what heading and airspeed you should choose to

reach your destination

At first we must find the resultant velocity of your plane and the wind

The south and west are perpendicular, then the resultant velocity is

→ v_{R}=\sqrt{(v_{p})^{2}+(v_{w})^{2}}

→ v_{p}=150 km/h ,  v_{w}=50 km/h

→ v_{R}=\sqrt{(150)^{2}+(50)^{2}}=158.11 km/h

To cancel the velocity of the wind, the pilot should maintain the velocity

of the plane at 158.11 km/h

The direction of the velocity is the angle between the resultant velocity

and the vertical (south)

→ The direction of the velocity is tan^{-1}\frac{50}{150}=18.4°

The direction of the velocity is 18.4° west of south

<em>You should choose airspeed 158.11 km/h at 18.4° west of south</em>

8 0
3 years ago
What is the escape speed of an electron launched from the surface of a 1.1-cm-diameter glass sphere that has been charged to 8.0
zimovet [89]
At surface,
v = kq/r

And potential energy of an electron is given by,
PE = -ev = -ekq/r

At escape velocity,
PE + KE = 0.
Therefore,
1/2mv^2 - ekq/r =0
1/2mv^2 = ekq/r
v = Sqrt [2ekq/mr], where v = escape velocity, e = 1.6*10^-19 C, k = 8.99*10^9 Nm^2/C^2, m = 9.11*10^-31 kg, r = 1.1*10^-2 m, q = 8*10^-9 C

Substituting;
v = Sqrt [(2*1.6*19^-19*8.99*10^9*8*10^-9)/(9.11*10^-31*1.1*10^-2)] = 47949357.23 m/s ≈ 4.795 *10^7 m/s
5 0
3 years ago
An athelete runs some distance before taking a long jump because : give answer
insens350 [35]
Hi Pupil Here's your answer ::



➡➡➡➡➡➡➡➡➡➡➡➡➡

An Athelete run some distance before taking a long jump because by running the Athelete gives himself larger inertia of motion.


⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅


Hope this helps .....

3 0
4 years ago
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lapo4ka [179]

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Explanation:

Water harvesting is a process of collection of rain water by using special water storing systems. This water storage practice helps during the scarcity of water like in dry summer seasons and in conditions of drought. Such water can be treated with filters to make it potable for drinking. But generally the water is used for the purpose of irrigation in the agricultural field and household sanitary requirements.

On the basis of the above description, By collecting run off during the rainy season for future irrigation increases the agricultural production is the correct option.

3 0
3 years ago
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2. Explain whether the size of an object's displacement could be greater than the distance the
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Answer:learn vocabulary, terms,and more with flashcards, games,and other study tools.size of an objects displacement could be greater than the distance the object travels.

Explanation:

4 0
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