From T = 2π√(l/g).
Since the lengths are the same, so that is a constant.
T α 1/√g
So the period T is inversely proportional to the square root of gravity g.
So the one with a bigger gravity g would have a shorter period
and
the one with smaller gravity g would have a longer period.
Therefore the period on the Moon with gravity of 1.63 m/s² would be longer period than that on the Earth with gravity of 9.81 m/s²
Answer: It's A
conduct smaller studies for more than a one-year period
Mass is Kg
Mol is the amount of substance
m is for meters
Answer: 567 N
Explanation:
If the weight of the person and the bike are supported equally by the two tires, this means that the force acting on each tire, is half of the total weight.
We know that the gauge pressure in one tire, by definition, is equal to the force on the tire, over the contact surface between each tire and the road, so we can write:
P= F/A = (mrider g + mbike g) / A = (Fgrider + 7.5 kg. 9.8 m/s2) / 703 mm2 (1)
As the pressure data is given in lb/in2, it is needed to convert to N/mm2, as follows:
65.5 lb/in2 = 0.455 N/mm2.
Replacing in (1), and solving for Fgrider, we have:
Fgrider = 567 N