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koban [17]
3 years ago
7

Which of the following represents a virtual image?

Physics
2 answers:
Naily [24]3 years ago
7 0

Answer:

Option (d)

Explanation:

In case of lenses, the image is said to be virtual if the rays of light after refraction appears to meet at a point.

If an object be placed to the left of a lens and image is also formed to the same side, i.e., left of the mirror, the image is said to be virtual .

By using the sigh conventions, the distance of image on the left has a negative sign .

So, - di be the location of virtual image.

erma4kov [3.2K]3 years ago
3 0
The answer for Apex is D. 
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Gravity __________ your kinetic energy when you are driving uphill and __________it when you are driving downhill.
Oxana [17]
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3 years ago
A cheetah can run 113 km/h in short busts. How far can a cheetah run in 0.25 hours (15 minutes)?
Fofino [41]
The cheetah can run 28,25 km
4 0
3 years ago
A spring with a spring constant of 50 N/m is stretched 15cm. What is the force and energy associated with this stretching?
Olenka [21]
Data:
F (force) = ? (Newton)
k (<span>Constant spring force) = 50 N/m
x (</span>Spring deformation) = 15 cm → 0.15 m

Formula:
F = k*x

Solving: 
F = k*x
F = 50*0.15
\boxed{\boxed{F = 7.5\:N}}\end{array}}\qquad\quad\checkmark

Data:
E (energy) = ? (joule)
k (Constant spring force) = 50 N/m
x (Spring deformation) = 15 cm → 0.15 m

Formula:
E = \frac{k*x^2}{2}

Solving:(Energy associated with this stretching)
E = \frac{k*x^2}{2}
E =  \frac{50*0.15^2}{2}
E =  \frac{50*0.0225}{2}
E =  \frac{1.125}{2}
\boxed{\boxed{E = 0.5625\:J}}\end{array}}\qquad\quad\checkmark

7 0
3 years ago
Monochromatic light of wavelength, lambda, is traveling in air. The light then strikes a thin film having an index of refraction
kumpel [21]

Answer:

The  correct option is  H

Explanation:

From the question we are told that

    The index of refraction of  coating is  n_1

       The  index of refraction of material  is  n_2

   

Generally the condition for constructive for a thin film interference is mathematically represented

            2 *  t  = [ m  + \frac{1}{2}] \frac{\lambda}{n_1 }

Here  t represents the thickness

For minimum thickness  m =  0

So

           2 *  t  =0  + \frac{1}{2}\frac{\lambda}{n_1 }

=>        t  =\frac{\lambda}{4n_1 }

3 0
3 years ago
A neutral solid metal sphere of radius 0.1 m is at the origin, polarized by a point charge of 2 × 10−8 C at location m. At locat
liraira [26]

Answer: E = 1.8 *10 ^{4} N

Explanation: The formulae for intensity of an electric field of a solid metal sphere relative to a point is given below

E =\frac{Kq}{r^{2} } r

where  k=9* 10^{9}N/m^{2}, q=2 *10 ^{-8} c , r = 0.1m r = is the position vector of the charge.

it has been stated in the question that the charge is placed at the center thus it has no position vector.

E=\frac{9 * 10^{9}* 2* 10^{-8}  }{0.1^{2} }\\ =\frac{18* 10^{1} }{0.01} \\=\frac{18* 10^{1} }{1 *10^{-2} } = 1.8*10^{4} N

6 0
3 years ago
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