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olya-2409 [2.1K]
3 years ago
7

Fill in each blank with an integer. In order to produce sp2 hybrid orbitals, ___ s atomic orbital(s), ___ p atomic orbital(s), a

nd ____ d atomic orbitals must be mixed/hybridized. After the hybridization, there is/are ___ unhybridized p orbital(s) around the central atom.
Chemistry
1 answer:
Y_Kistochka [10]3 years ago
6 0

Answer:

1, 2, 0, 1

Explanation:

The bonds between atoms can be explained in terms of hybrid orbitals. The kind of hybrid orbital depends on the kind and number of atomic orbitals that hybridize.

In order to produce sp² hybrid orbitals, 1 s atomic orbital, 2 p atomic orbitals, and 0 d atomic orbitals must be mixed/hybridized.

There are 3 p orbitals in each p sublevel.

After the hybridization, there is 1 unhybridized p orbital around the central atom.

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Calcium Oxide will react with ammonium chloride to produce ammonia gas, water vapor, and calcium chloride. If only 16.3 g of amm
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Answer:

                     %age Yield  =  22.72 %

Explanation:

                    The balance chemical equation is as follow;

                           2 NH₄Cl + CaO → 2 NH₃ + CaCl₂ + H₂O

Step 1: <u>Calculate Moles of CaO, NH₄Cl and NH₃;</u>

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        Moles  =  Mass / M.Mass

        Moles  =  112 g / 56.07 g/mol

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        Moles  =  224 g / 53.49 g/mol

        Moles  =  4.18 moles of NH₄Cl

NH₃:

        Moles  =  Mass / M.Mass

        Moles  =  16.3 g / 17.03 g/mol

        Moles  =  0.95 moles of NH₃

Step 2: <u>Calculate Limiting reagent as:</u>

According to equation.

                   2 moles of NH₄Cl reacts with  =  1 mole of CaO

So,

              4.18 moles of NH₄Cl will react with  =  X moles of CaO

Solving for X,

                     X =  4.18 mol × 1 mol / 2 mol

                     X  =  2.09 mol of CaO

This means that none of the given reagent is limiting reagent. They both are almost equal in number of moles.

Step 3: <u>Calculate Theoretical Yield of NH₃ as;</u>

According to equation.

                   2 moles of NH₄Cl produced  =  2 moles of NH₃

So,

              4.18 moles of NH₄Cl will produce  =  X moles of NH₃

Solving for X,

                     X =  4.18 mol × 2 mol / 2 mol

                     X  =  4.18 mol of NH₃

Step 4: <u>Calculate Percentage Yield as;</u>

             %age Yield  =  Actual Yield / Theoretical Yield × 100

             %age Yield  =  0.95 mol / 4.18 × 100

             %age Yield  =  22.72 %

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