Answer:
D) The amount of heat a substance can hold.
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
The substances with higher value of specific heat capacity require more heat to raise the temperature by one degree as compared the substances having low value of specific heat capacity.
For example,
The specific heat capacity of oil is 1.57 j/g. K and for water is 4.18 j/g.K. So, water take a time to increase its temperature by one degree by absorbing more heat while oil will heat up faster by absorbing less amount of heat.
Hello!
Given the density of mercury being 13.57 g/mL, and the mass of 52 kilograms, we need to find the volume.
To find the volume, we need to divide mass by density (V = m/d).
Notice that you are given 52 kilograms, but not grams. To convert kilograms to grams, you need to multiply it by 1000.
52 x 1000 = 52000 grams
With the correct measurements, we can find the volume.
V = 52000 grams / 13.56 grams/milliliter
V ≈ 3834.80826
Therefore, the volume of the mercury is about 3,834.81 mL.
Answer:
How high the plants grow in the different soils.
Explanation:
The dependent variable is what happens as a result of what the experimenter changes.
The experimenter could measure how high the plants grow when placed in soil with different pH values.
The greatest concentration of atomic mass is the atom's nucleus. This is because the nucleus is made up out of protons and neutrons while the electrons surrounding the nucleus have a very small mass.
Answer:
0.13 M ( 2 s.f)
Explanation:
2Cl2O5 (g)-->2Cl2(g) +5O2 (g)
rate= (17.4 M -1 .s -1 ) [Cl2O5]2
From the rte above, we can tell that our rate constant (k) = 17.4 M -1 .s -1
The units of k tells us this is a second order reaction.
Initial Concentration [A]o = 1.46M
Final Concentration [A] = ?
Time = 0.400s
The integrated rate law for second order reactions is given as;
1 / [A] = (1 / [A]o) + kt
1 / [A] = [ (1/ 1.46) + (17.4 * 0.4) ]
1 / [A] = 0.6849 + 6.96
1 / [A] = 7.6496
[A] = 1 / 7.6496
[A] = 0.13073 M ≈ 0.13 M ( 2 s.f)