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Lisa [10]
3 years ago
14

How many additional grams of KOH are required to increase the concentration of the solution to 0.500 m? G

Chemistry
1 answer:
katen-ka-za [31]3 years ago
5 0

Answer:

21.9g

Explanation:

This is the answer if you are on edginuity,

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How many moles of water will be produced from the combustion of 0.27 moles of CH3OH?
Valentin [98]

Answer:

0.54 mole of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2CH3OH + 3O2 —> 2CO2 + 4H2O

From the balanced equation above,

2 moles of CH3OH reacted to produce 4 moles of water.

Finally, we shall determine the number of mole of water (H2O) produced by the reaction of 0.27 moles of CH3OH. This can be obtained as follow:

From the balanced equation above,

2 moles of CH3OH reacted to produce 4 moles of water.

Therefore, 0.27 moles of CH3OH will react to produce = (0.27 × 4)/2 = 0.54 mole of H2O.

Thus, 0.54 mole of H2O is produced from the reaction.

5 0
2 years ago
How many electrons are shared in a double covalent bond?
AleksAgata [21]
In a double covalent bonds there are 4 valence electrons that are shared.
8 0
3 years ago
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A gas occupies a volume of 2.4 L at 14.1 kPa. What volume will the gas occupy at 84.6 kPa?
Naddik [55]

Answer:

  • <u>0.40 L</u>

Explanation:

Boyle's law for gases states that, at constant temperature, the volume and pressure of a fixed amount of gas are inversely related.

Mathematically, that is:

  • PV = constant

  • P₁V₁ = P₂V₂

Here, you have:

  • V₁ = 2.4 L
  • P₁ = 14.1 Kpa
  • P₂ = 84.6 KPa
  • V₂ = ?

Then, you can solve for V₂:

  • V₂ = P₁V₁ / P₂

Substitute and compute:

  • V₂ = 14.1 KPa × 2.4L / 84.6 KPa = 0.40 L ← answer
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