The use of wind power to generate electricity is a big advantage because it is____.
2 answers:
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Answer:
a) F₁ = 267.3 N, N₁ = 1300 N, b) μ = 0.324
Explanation:
For this exercise we use the rotational equilibrium condition, we have a reference system is the floor and the anticlockwise rotations as positive, in the adjoint we can see a diagram of the forces
let's use subscript 1 for the ladder and 2 for the firefighter
∑ τ = 0
-W₁ x₁ - W₂ x₂ + N₁ y = 0
N₁ = (1)
the center of mass of the ladder is at its geometric center,
d = L / 2 = 15/2 = 7.5 m
cos 60 = x₁ / d₁
x₁ = d₁ cos 60
x₁ = 7.5 cos 60
x₁ = 3.75 m
for the firefighter d₂ = 4 m
cos 60 = x₂ / d₂
x₂ = d₂ cos 60
x₂ = 4 cos 60 = 2 m
for the fulcrum d₃ = 15 m
sin 60 = y / d₃
y = d₃ sin 60
y = 15 sin 60
y = 13 m
we look for the Normal by substituting in equation 1
N₂ =
N₂ = 267.3 N
now let's use the translational equilibrium relations
X axis
F₁ - N₂ = 0
F₁ = N₂
F₁ = 267.3 N
Axis y
N₁ - W₁ -W₂ = 0
N₁ = W₁ + W₂
N₁ = 500 + 800
N₁ = 1300 N
b) for this case change the firefighter's distance d₂ = 9 m
x₂ = 9 cos 60
x₂ = 4.5 m
we substitute in 1
N₂ = \frac{500 \ 3.75 \ + 800 \ 4.5}{13}
N₂ = 421.15 N
of the translational equilibrium equation on the x-axis
fr = F₁ = N₂
fr = 421.15 N
friction force has the expression
fr = μ N
in this case the reaction of the Earth to the support of the ladder is N1 = 1300N
μ = fr / N₁
μ = 421.15 / 1300
μ = 0.324
Newton's second law and graphical analysis allow us to find the correct answer for the measure of the constant b is:
D) Stack several filters to change the mass measure the acceleration of the system.
Newton's second law establishes a relationship between the net force, the mass and the acceleration of the bodies.
∑ F = m a
Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.
They indicate that the drag force on the filters is
F = - b v
Where b is a positive constant that depends on the shape and area of the filter and v is the speed of the filter.
Let's write Newton's second law.
W - fr = ma
W -bv = ma
In the experiment the students indicate that they can measure the position, velocity and acceleration of the body.
Based on the above, if we place several filter weights and measure their speed and acceleration in each case, we can make a graph of velocity versus acceleration, we can take the value of the constant b from the slope.
Let's analyze the different answers:
A) False. The constant b depends on the shape of the filter therefore it must be kept constant.
B) False. The constant depends on the area, so it must be kept constant.
C) May be. In this case, since we have the terminal velocity, the acceleration is zero, Newton's second law remains.
B v - W = 0
b =
The problem with the method is the difficulty of measuring the compression terminal velocity.
D) True. According to the discussion of the velocity versus acceleration. graph, the constant b is equal to the slope of the graph.
E) May be. The problem with this method is finding a reliable value for the terminal velocity.
In conclusion, using Newton's second law and graphical analysis we can find the correct answer for the measure of the constant b is:
D) Stack several filters to change the mass measure the acceleration of the system.
Learn more here: brainly.com/question/2441565
The height risen by water in the bell after enough time has passed for the air to reach thermal equilibrium is 3.8 m.
<h3>Pressure and temperature at equilibrium </h3>
The relationship between pressure and temperature can be used to determine the height risen by the water.
where;
- V₁ = AL
- V₂ = A(L - y)
- P₁ = Pa
- P₂ = Pa + ρgh
- T₁ = 20⁰C = 293 K
- T₂ = 10⁰ C = 283 k
Thus, the height risen by water in the bell after enough time has passed for the air to reach thermal equilibrium is 3.8 m.
The complete question is below:
A diving bell is a 4.2 m -tall cylinder closed at the upper end but open at the lower end. The temperature of the air in the bell is 20 °C. The bell is lowered into the ocean until its lower end is 100 m deep. The temperature at that depth is 10°C. How high does the water rise in the bell after enough time has passed for the air to reach thermal equilibrium?
Learn more about thermal equilibrium here: brainly.com/question/9459470
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