Answer:
Option A. the hydroxyl group (-OH)
Explanation:
Ethanol, CH₃CH₂OH belongs to the class of organic compound called alkanol.
They have general formula as R–OH
Where
R => is an alkyl group
OH => is the hydroxyl group
The hydroxyl group (OH) is the functional group of the alkanol (alcohol)
Answer:
397 L
Explanation:
Recall the ideal gas law:
![\displaystyle PV = nRT](https://tex.z-dn.net/?f=%5Cdisplaystyle%20PV%20%3D%20nRT)
If temperature and pressure stays constant, we can rearrange all constant variables onto one side of the equation:
![\displaystyle \frac{P}{RT} = \frac{n}{V}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BP%7D%7BRT%7D%20%3D%20%5Cfrac%7Bn%7D%7BV%7D)
The left-hand side is simply some constant. Hence, we can write that:
![\displaystyle \frac{n_1}{V_1} = \frac{n_2}{V_2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bn_1%7D%7BV_1%7D%20%3D%20%5Cfrac%7Bn_2%7D%7BV_2%7D)
Substitute in known values:
![\displaystyle \frac{(3.31 \text{ mol})}{(100 \text{ L})} = \frac{(13.15\text{ mol })}{V_2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B%283.31%20%5Ctext%7B%20mol%7D%29%7D%7B%28100%20%5Ctext%7B%20L%7D%29%7D%20%20%3D%20%5Cfrac%7B%2813.15%5Ctext%7B%20mol%20%7D%29%7D%7BV_2%7D)
Solving for <em>V</em>₂ yields:
![\displaystyle V_2 = \frac{(100 \text{ L})(13.15)}{3.31} = 397 \text{ L}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20V_2%20%3D%20%5Cfrac%7B%28100%20%5Ctext%7B%20L%7D%29%2813.15%29%7D%7B3.31%7D%20%3D%20397%20%5Ctext%7B%20L%7D)
In conclusion, 13.15 moles of argon will occupy 397* L under the same temperature and pressure.
(Assuming 100 L has three significant figures.)
Answer:
x=30
Explanation:
I will try to explain with a drawing.
This is a rule of three.
If you are wondering what the rule of three is. It's when u have 3 informations and you solve.
Its a form of anaesthesia used by dentists
hope that helsp