OK, this is pretty interesting.
First get out your parameters.
Pressure of gas, P= 1.5×10^5 Pa
Initial volume, V1=0.0002m³
Final volume, V2=0.0006m³
Heat change, ∆H= +32J (it is positive since it was absorbed.)
Now you can solve.
∆U= ∆H—P∆V
∆U=32J—(1.5×10^5×(0.0006—0.0002))
∆U=32J—(1.5×10^5×0.0004)
∆U=32J—(1.5×10^5×4×10^—4)
∆U=32—60
∆U=—28J
That corresponds to option C.
The answer is (C) Diagram 3
The net pull is 17.49... Newtons (rounded), in the direction that is about 31 decrees north of east.
The answer is tropical rainforest
<h3><u>Answer</u>;</h3>
= 22°
<h3><u>Explanation</u>;</h3>
- According to Snell's law, the ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant. The constant value is called the refractive index of the second medium with respect to the first.
- Therefore; Sin i/Sin r = η
In this case; Angle of incidence = 90° -60° =30°, angle of refraction =? and η = 1.33
Thus;
Sin 30 / Sin r = 1.33
Sin r = Sin 30°/1.33
= 0.3759
r = Sin^-1 0.3759
= 22.08
<u>≈ 22°</u>