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alex41 [277]
3 years ago
5

What is your understanding of science?​

Physics
1 answer:
Delvig [45]3 years ago
6 0

Answer:Science is a method of learning things about the world and environment we live in today . It gives us a better understanding of the natural world and how it works

Explanation:

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"As you sit in a fishing boat, you notice that 12 waves pass the boat every 45 s. If the distance from one crest to the next is
Alchen [17]

Answer:

2.4564 m/s

Explanation:

Number of waves in 1 second

\dfrac{12}{45}=0.267\ Hz

This is the frequency 0.267 Hz

The distance mentioned in the question is the

\lambda = Wavelength = 9.2 m

The speed of wave is

v=f\lambda

\Rightarrow v=0.267\times 9.2

\Rightarrow v=2.4564\ m/s

The speed of the wave is 2.4564 m/s

4 0
3 years ago
A football player kicks a field goal from a distance of 45 m from the goalpost. The football is launched at a 35° angle above th
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Answer:  try searching It up on go0gle

Explanation:

7 0
3 years ago
calculate earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the s
IceJOKER [234]

Answer:

Hello your question is incomplete below is the complete question

Calculate Earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the sun, Take the eccentricity of Earth's orbit to be 1/60 and its Semimajor axis to be 93,000,000

answer : V = 1.624* 10^-5 m/s

Explanation:

First we have to calculate the value of a

a = 93 * 10^6 mile/m  * 1609.344 m

  = 149.668 * 10^8 m

next we will express the distance between the earth and the sun

r = \frac{a(1-E^2)}{1+Ecos\beta }   --------- (1)

a = 149.668 * 10^8

E (eccentricity ) = ( 1/60 )^2

\beta = 90°

input the given values into equation 1 above

r = 149.626 * 10^9 m

next calculate the Earths velocity of approach towards the sun using this equation

v^2 = \frac{4\pi^2 }{r_{c} }   ------ (2)

Note :

Rc = 149.626 * 10^9 m

equation 2 becomes

(V^2 = (\frac{4\pi^{2}  }{149.626*10^9})

therefore : V = 1.624* 10^-5 m/s

4 0
4 years ago
A person wants to fire a water balloon cannon such that it hits a target 100m100m away. if the cannon can only be launched at 45
vladimir2022 [97]
<span>31.3 m/s Since the water balloon is being launched at a 45 degree angle, the horizontal and vertical speeds will be identical. Also the time the balloon takes to reach its peak altitude will match the time it takes to fall. So let's create a few expressions about what we know. Distance the water balloon travels at velocity v for time t d = vt Total time required for the entire trip is double since the balloon goes up, then goes down t = 2v/a Now let's plug in the numbers we have, assuming the acceleration due to gravity is 9.8 m/s^2 t = 2v/9.8 100 = vt Substitute 2v/9.8 for t in the 2nd formula 100 = v(2v/9.8) Solve for v. 100 = v(2v/9.8) 100 = 2v^2/9.8 980. = 2v^2 490 = v^2 22.13594 = v So we now know that both the horizontal velocity and vertical velocity needed is 22.13594 m/s. Let's verify that 2*22.13594 / 9.8 = 4.51754 So it will take 4.51754 second for the balloon to hit the ground after being launched. 4.51754 * 22.13594 = 100 And during that time it will travel 100 meters horizontally. But we need to know the total velocity. And the Pythagorean theorem comes to the rescue. Just square the 2 velocities, add them together, and take the square root. We already know the square is 490 from the work above, so sqrt(490+490) = sqrt(980) = 31.30495 m/s</span>
3 0
3 years ago
Aristotle was a true scientist. True or false?
leonid [27]
No, because he was a philosopher 
4 0
4 years ago
Read 2 more answers
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