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4 years ago

Why are the electron affinities of the group 4a elements more negative than those of the group 5a elements?

1 answer:

8 0

The electron subshells in the atoms of group 5a elements discourage electron addition.

This is because the subshells in the group 5a elements are already half-filled, which is a more stable electronic configuration that that which would be achieved if another electron was added.
Meanwhile, group 4a elements' subshell becomes half-filled when an electron is added, making them somewhat stable. This means that they prefer electron addition.

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Fossil originally has 254 g of carbon-14 but currently has 127 g of carbon-14 the fossil is most likely

KATRIN_1 [288]

Answer:

The answer to your question is: letter C) 5730

Explanation:

Data

Originally Carbon - 14 254 g

Currently Carbon - 14 127 g

Half-life of Carbon -14 is when half of the original amount of Carbon disintegrates.

Then, if originally there were 254 and now there are 127, only one half life passed.

Half life of carbon -14 is 5730 years old.

8 0

4 years ago

Qual e o maior orgao do corpo humano

morpeh [17]

El órgano interno más grande es el hígado. Pero el órgano externo más grande es la piel, <span>Espero que esto ayudó!</span>

6 0

3 years ago

Which has the largest atomic radius calcium bromide barium and astatine

Fantom [35]

The one with the largest atomic radius is barium

Hoped this helped:)

7 0

4 years ago

Read 2 more answers

You have a substance and begin a set of experiments in which you break it down into other substances through chemical reactions.

a_sh-v [17]

They're elements. Elements are the simplest form of any substance that cannot be broken down by any chemical methods, including electrolysis or even heat. Examples include oxygen, hydrogen etc.

3 0

4 years ago

I NEED HELP PLEASE! :)

riadik2000 [5.3K]

Answer:

$C_{21} H_{23} NO_{5}$

Explanation:

First thing is we have assume all the percents are grams so we have

68.279g C, 6.2760g H, 3.7898g N, and 21.656g O

Now convert each gram to moles by dividing the the molar mass of each element

68.279g/12.01g= 5.685 moles of C

6.2760g/1.01g= 6.214 moles of H

3.7898g N/14.01g= 0.271 moles of N

21.656g O/ 16.00g= 1.354 moles of O

Now to find the lowest ratios divide all the moles by the smallest number of moles you found, in our case, the smallest moles is 0.271 moles of N so divide everything by that....

5.685 moles/0.271 moles ------> ~21 C

6.214 moles/0.271 moles --------> ~23 H

0.271 moles / 0.271 moles ---------> 1 N

1.354 moles/ 0.271 moles ----------> ~5 O

So the empirical formula is C21H23NO5 $C_{21} H_{23} NO_{5}$

5 0

3 years ago