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3 years ago

A mineral always contains certain ___

Chemistry

2 answers:

Vesnalui [34]3 years ago

6 0

Answer:elements in definite proportions.

Explanation:

const2013 [10]3 years ago

4 0

A mineral always contain certain elements in definite proportions

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(pls help !!) question is in image

Anastaziya [24]

Answer:

the second option is correct

Explanation:

maybe I think b is correct

6 0

2 years ago

2. Use the Henderson-Hasselbalch equation to estimate the pH of a buffer solution that is composed of 20 mL of 10 M sodium forma

Mkey [24]

Answer:

pH of buffer =4.75

Explanation:

The pH of buffer solution is calculated using Henderson Hassalbalch's equation:

$pH=pKa+log[\frac{[salt]}{[acid]}$

Given:

pKa = 3.75

concentration of acid = concentration of formic acid = 1 M

concentration of salt = concentration of sodium formate = 10 M

$pH=3.75+log[\frac{10}{1}]=3.75+1=4.75$

pH of buffer =4.75

7 0

3 years ago

Making models involves creating representations of complex objects or processes to help people study and understand things that

swat32

Somewhat false
observations can be made of a model of the statue of liberty, say, or in real line

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2 years ago

What diffuses more quickly: tetracarbon decahydride (C4H10) or iodine (12)? By how much?

ValentinkaMS [17]

Answer: Butane will effuse more quickly because it has a smaller molar mass

Explanation:

Molar mass of C4H10 = 58.123 g/mole

Molar mass of I2 = 253.808 g/mole

5 0

3 years ago

In Lab 10 you make a stock solution of salicylic acid, and then four dilutions. The stock solution is made by diluting 5.00 ml o

Zigmanuir [339]

Answer:

Stock solution = 1.25 *10^-3 M

Dilution 1 = 5*10^-4 M

Dilution 2= 3.75 * 10^-4 M

Dilution 3 = 2.5 *10^-4 M

Dilution 4 = 1.25 *10^-4 M

Explanation:

Step 1: Data given

The stock solution is made by diluting 5.00 ml of 1.250 x 10-2 M salicylic acid in 50.00 mL of solution.

Step 2: Calculate the concentration of the stock solution:

M1*V1 = M2*V2

⇒ with M1 = the initial concentration = 1.250 *10^-2 M

⇒ with V1 = 5 mL = 5*10^-3 L

⇒ with M2 = TO BE DETERMINED

⇒ with V2 = 50 mL = 50 *10^-3 L

M2 = (M1*V1)/V2

M2 = (1.250 *10^-2 * 5*10^-3 L) / 50 *10^-3

M2 = 0.00125 M = 1.25 *10^-3 M

Step 3: Calculate dilution 1

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 10 *10^-3)/(25*10^-3L)

M2 = 0.0005 M = 5*10^-4 M

Step 4: Calculate dilution 2

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 10 * 7.5*10^-3)/(25*10^-3)

M2 = 0.000375 M = 3.75 * 10^-4 M

Step 5: Calculate dilution 3

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 5*10^-3) /(25*10^-3)

M2 = 0.00025 M = 2.5 *10^-4 M

Step 6: Calculate dilution 4

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 2.5*10^-3)/(25*10^-3)

M2 = 0.000125 M = 1.25 *10^-4 M

5 0

3 years ago