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alukav5142 [94]
3 years ago
7

Velocity components in an incompressible flow are: v = 3xy + x^2 y: w = 0. Determine the velocity component in the x-direction.

Engineering
1 answer:
cupoosta [38]3 years ago
3 0

Answer:

Velocity component in x-direction u=-\frac{3}{2}x^2-\frac{1}{3}x^3.

Explanation:

   v=3xy+x^{2}y

We know that for incompressible flow

   \frac{\partial u}{\partial x}+\frac{\partial v}{\partial y}=0

\frac{\partial v}{\partial y}=3x+x^{2}

So   \frac{\partial u}{\partial x}+3x+x^{2}=0

\frac{\partial u}{\partial x}= -3x-x^{2}

By integrate with respect to x,we will find

u=-\frac{3}{2}x^2-\frac{1}{3}x^3+C

So the velocity component in x-direction u=-\frac{3}{2}x^2-\frac{1}{3}x^3.

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1 import java.util.Scanner; 3 public class EqualityAndRelational { 4 public static void main (String args) args) { int userBonus
Anastaziya [24]

Missing Part of the Question

Complete the expression so that userPoints is assigned with 0 if userBonus is greater than 20 (second branch). Otherwise, userPoints is assigned with 10 (first branch

import java.util.Scanner;

public class EqualityAndRelational {

public static void main (String args) args) {

int userBonus; int userPoints;

userPoints=0;

Scanner scnr = new Scanner(System.in);

userBonus = scnr.nextInt();

// Program will be tested with values : 15, 20, 25, 30, 35. 12 13 14 15 16 17 18 19

( Your solution goes here)

{

userPoints= 10 ;

}

else {

userPoints = 0;

}

}

}

Answer;

Replace

( Your solution goes here)

With

if(userBonus>20).

The full program becomes

import java.util.Scanner;

public class EqualityAndRelational {

public static void main (String args) args) {

int userBonus; int userPoints;

userPoints=0;

Scanner scnr = new Scanner(System.in);

userBonus = scnr.nextInt();

// Program will be tested with values : 15, 20, 25, 30, 35. 12 13 14 15 16 17 18 19

if(userBonus>20)

{

userPoints= 10 ;

}

else {

userPoints = 0;

}

}

}

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Answer:

C. Centrifugal pump

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Dynamic pumps which are also known as centrifugal pumps are the ones widely used when we require high discharge. This is because they deal with transfer of fluids with low viscosity in flow rates that are high. Another reason is that they are also very good with low pressure installation.

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Answer:

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