Answer:
b. equal to the specific entropy of the gas at the inlet.
Explanation:
Isentropic process is the process in which the entropy of the system remains unchanged. The word isentropic is formed from the combination of the prefix "iso" which means "equal" and the word entropy.
If a process is completely reversible, without the need to provide energy in the form of heat, then the process is isentropic.
Answer:
The correct answer is option 'B': Load is far from fulcrum and the effort is applied near the fulcrum
Explanation:
A lever works on the principle of balancing of torques. The torque about the fulcrum by the load should be equal to the torque by the applied effort. Since we know that the torque is proportional to both the force and the distance it is applied from the distance from the axis of rotation. A lever is used when we need to lift a heavy load by utilizing this effect of the lever arm.
A mechanical disadvantage occurs when we are not able to lift the weight easily due to the fact we apply effort near the fulcrum.
Answer:
If the heat engine operates for one hour:
a) the fuel cost at Carnot efficiency for fuel 1 is $409.09 while fuel 2 is $421.88.
b) the fuel cost at 40% of Carnot efficiency for fuel 1 is $1022.73 while fuel 2 is $1054.68.
In both cases the total cost of using fuel 1 is minor, therefore it is recommended to use this fuel over fuel 2. The final observation is that fuel 1 is cheaper.
Explanation:
The Carnot efficiency is obtained as:
![\epsilon_{car}=1-\frac{T_c}{T_H}](https://tex.z-dn.net/?f=%5Cepsilon_%7Bcar%7D%3D1-%5Cfrac%7BT_c%7D%7BT_H%7D)
Where
is the atmospheric temperature and
is the maximum burn temperature.
For the case (B), the efficiency we will use is:
![\epsilon_{b}=0.4\epsilon_{car}](https://tex.z-dn.net/?f=%5Cepsilon_%7Bb%7D%3D0.4%5Cepsilon_%7Bcar%7D)
The work done by the engine can be calculated as:
where Hv is the heat value.
If the average net power of the engine is work over time, considering a net power of 2.5MW for 1 hour (3600s), we can calculate the mass of fuel used in each case.
![m=\frac{P\cdot t}{\epsilon H_v}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7BP%5Ccdot%20t%7D%7B%5Cepsilon%20H_v%7D)
If we want to calculate the total fuel cost, we only have to multiply the fuel mass with the cost per kilogram.
![TC=m\cdot c](https://tex.z-dn.net/?f=TC%3Dm%5Ccdot%20c)
Full Question
1. Correct the following code and
2. Convert the do while loop the following code to a while loop
declare integer product
declare integer number
product = 0
do while product < 100
display ""Type your number""
input number
product = number * 10
loop
display product
End While
Answer:
1. Code Correction
The errors in the code segment are:
a. The use of do while on line 4
You either use do or while product < 100
b. The use of double "" as open and end quotes for the string literal on line 5
c. The use of "loop" statement on line 7
The correction of the code segment is as follows:
declare integer product
declare integer number
product = 0
while product < 100
display "Type your number"
input number
product = number * 10
display product
End While
2. The same code segment using a do-while statement
declare integer product
declare integer number
product = 0
Do
display "Type your number"
input number
product = number * 10
display product
while product < 100
Answer:
Heat transfer rate(Q)= 1.197kW
Power output(W)=68.803kW