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tigry1 [53]
3 years ago
9

Convert 0.74Kcal/min to cal/sec

Physics
1 answer:
zaharov [31]3 years ago
5 0
0.74Kcal/min = 0.74*1000cal/60 sec = 12.33 cal/sec
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Vector ????⃗ has a magnitude of 16.6 and is at an angle of 50.5∘ counterclockwise from the +x‑axis. Vector ????⃗ has a magnitude
natka813 [3]

Answer:

For vector u, x component = 10.558 and  y component =12.808

unit vector = 0.636 i+ 0.7716 j

For vector v, x component = 23.6316 and y component = -6.464

unit vector = 0.9645 i-0.2638 j

Explanation:

Let the vector u has magnitude 16.6

u makes an angle of 50.5° from x axis

So u_x=ucos\Theta =16.6\times cos50.5=10.558

Vertical component u_y=usin\Theta =16.6\times sin50.5=12.808

So vector u will be u = 10.558 i+12.808 j

Unit vector u=\frac{10.558i+12.808j}{\sqrt{10.558^2+12.808^2}}=0.636i+0.7716j

Now in second case let vector v has a magnitude of 24.5

Making an angle with -15.3° from x axis

So horizontal component v_x=vcos\Theta =24.5\times cos(-15.3)=23.6316

Vertical component v_y=vsin\Theta =24.5\times sin(-15.3)=-6.464

So vector v will be 23.6316 i - 6.464 j

Unit vector of v =\frac{23.6316i-6.464}{\sqrt{23.6316^2+6.464^2}}=0.9645i-0.2638j

8 0
2 years ago
Pls help me with this fast. I will mark brainiest
denis23 [38]

Answer:

a) 70, 95

b) 95-70= 25cc

c) density= mass/volume

102/25

=4.08g/cc

5 0
2 years ago
A car tire is filled with air at pressure 325000 pa at 303 K. When the tire cools,its pressure reduces to 299000 Pa. What is the
max2010maxim [7]

Answer:

new temperature of the tire will be 278.76 K

Explanation:

when the temperature increases, the particles will have greater kinetic energy and also the pressure will be increase for the gas particles.

so when the temperature increases, pressure  will also increase  and vice versa

 T is directly proportional to P

T1  = initial temperature= 303 k

P1= Initial pressure =  325000 pa

T2= Final temperature=  ?

P2= Final pressure =   299000 pa

mathematically

P1/T1= P2/T2

T2= P2 x T1/P1

T2 = 299000 x 303/ 325000=  278.76 k

6 0
3 years ago
Read 2 more answers
A mystery element has three isotopes of the following masses and percent abundances: 93.597 amu at 23.63 % abundance, 96.191 amu
iogann1982 [59]

Answer:

92.397amu

Explanation: The exact amu of the mystery element is obtained by multiplying the relative abundance of each individual isotope by  its respective amu and then summing the results.

The sum of the total relative abundance for all the isotopes should be 100%.

However, the relative abundance of the isotope with 95.502amu is not given; therefore to obtain it we subtract the sum of the known relative abundances from 100% as follows:

Relative abundance of isotope with 95.502amu = 100-(23.63+30.53) = 42.84%

8 0
3 years ago
Electric potential energy can be maximized when
Leokris [45]

Answer:

d and f

Explanation:

4 0
3 years ago
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