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Orlov [11]
3 years ago
9

Three ways in which water reaches the atmosphere and which way accounts for most of the water in the atmosphere???

Physics
1 answer:
KIM [24]3 years ago
8 0

1: Evaporation, this accounts for the most

2: Transpiration, second most

3: Sublimation, third most

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The main water line enters a house on the first floor. The line has a gauge pressure of 1.94 x 105 Pa. (a) A faucet on the secon
Ad libitum [116K]

Answer

given,

gauge pressure =   1.94 x 10⁵ Pa

Pressure due to 4.90 m column of water

= ρ g h

= (4.90) x  (1000)  x (9.8) Pa

= 48020 Pa

Gauge pressure of second floor faucet

= 1.94 x 10⁵Pa - 48020 Pa

P_g= 145980 Pa

( b )

Let h = height of faucet from which no water can flow even if open

P = ρ g h

1.94 x 10⁵  = h x(1000) x (9.8)

h = 19.79 m

4 0
3 years ago
What energy is directly dependent upon velocity and mass?
erastova [34]

Answer:

Kinetic energy

Explanation:

3 0
3 years ago
A hair dryer draws a current of 10 A plugged into a 120 V outlet. What is the resistance of the hair dryer?
Ganezh [65]
<span>This problem can be solved by the formula used to find resistance. The formula is R=V/I which basically means divide the Voltage by the Current to find the Resistance in an object. Ohm's law.</span>
8 0
3 years ago
Read 2 more answers
assume the suns total energy output is 4.0 * 10^26 watts, and 1 watt is 1 joule/second. assume 4.3 * 10^-12 J is released from e
Dmitry [639]

Answer:

9.3\cdot 10^{37}

Explanation:

Power is defined as the energy produced (E) per unit of time (t):

P= \frac{E}{t}

This means that the energy produced in the Sun each second (1 s), given the power P=4.0\cdot 10^{26}W, is

E=Pt=(4.0\cdot 10^{26}W)(1s )=4.0\cdot 10^{26} J

Each p-p chain reaction produces an amount of energy of

E_1 = 4.3\cdot 10^{-12} J

in order to get the total number of p-p chain reactions per second, we need to divide the total energy produced per second by the energy produced by each reaction:

n=\frac{E}{E_1}=\frac{4.0\cdot 10^{26} J}{4.3\cdot 10^{-12} J}=9.3\cdot 10^{37}

3 0
3 years ago
The time delay between transmission and the arrival of the reflected wave of a signal using ultrasound traveling through a piece
Brilliant_brown [7]

Answer:

10.01 cm

Explanation:

Given that,

The time delay between transmission and the arrival of the reflected wave of a signal using ultrasound traveling through a piece of fat tissue was 0.13 ms.

The average propagation speed for sound in body tissue is 1540 m/s.

We need to find the depth when the reflection occur. We know that, the distance is double when transmitting and arriving. So,

v=\dfrac{2d}{t}\\\\d=\dfrac{vt}{2}\\\\d=\dfrac{1540\times 0.13\times 10^{-3}}{2}\\\\d= $$0.1001\ m

or

d = 10.01 cm

So, the reflection will occur at 10.01 cm.

8 0
2 years ago
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