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oee [108]
3 years ago
13

A spinner is divided into four equal sections that are numbered 2, 4, 5, and 7. The spinner is spun twice. How many outcomes hav

e a sum less than 7 and contain at least one even number?
Physics
1 answer:
Lubov Fominskaja [6]3 years ago
5 0

Answer:

3 outcomes

Explanation:

Since the sum must be less than 7, then one of them cannot be 7 because 7 + something > 7. Also the minimum number is 2 so one of them cannot be 5 either because 5 + 2 = 7 is not less than 7.

So the only options we have here is 2 and 4. The outcome of this is

(2,2) so 2 + 2 = 4 < 7

(2,4) so 2 + 4 = 6 < 7

(4,2) so 4 + 2 = 6 < 7

Note that (4,4) is not possible because 4 + 4 = 8 > 7

So 3 outcomes have a sum less than 7 and contain at least one even number

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\omega = 6.3 \times \frac{1 \: rev}{60 \: seconds}

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