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Rashid [163]
2 years ago
15

An x-ray beam of a certain wavelength is incident on a crystal, at 30.7° to a certain family of reflecting planes of spacing 33.

4 pm. If the reflection from those planes is of the first order, what is the wavelength of the x rays?
Physics
2 answers:
marissa [1.9K]2 years ago
4 0

Answer:

The wavelength of the x rays is 34.104 pm

Explanation:

Given data:

θ = incidence angle = 30.7°

d = space between planes = 33.4 pm = 33.4 x10⁻¹²m

According Bragg's expression:

n\lambda =2dsin\theta \\n=1,first-order\\\lambda =  2dsin\theta\\\lambda =2*33.4*sin30.7=34.104pm

klemol [59]2 years ago
3 0

Answer:

λ=34.068pm

Explanation:

Wavelength λ=2dsinθ

λ=2(33.4pm)sin30.7

λ=2(33.4pm) * 0.510

λ=66.8* sin30.7

λ=66.8*0.510

λ=34.068pm

X-rays are usually produced by charged particles that are accelerating or decelerating such as a beam of electrons striking a metal plate in an X-ray tube.

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bulgar [2K]

Answer:

The balloon prohibits the flow of air through the air capacitor.

Explanation:

Just like an electric capacitor has an insulator between the plates, the air capacitor has a balloon between the chambers.

6 0
3 years ago
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What would be the final temperature if you mixed a liter of 40C water with 2 liters of 20C water?
riadik2000 [5.3K]

Answer:

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33 ∘ C

Explanation:

i hope this helps :)

5 0
2 years ago
An internal resistance of 5 ohm and a battery of 15 ohm is connected to a resistance of 20 ohm calculate the electric current
Allushta [10]

Answer:

.6 A

Explanation:

Battery 15 VOLTS

V = IR

V / R = I

15 / ( 5+20) = .6 amps

5 0
2 years ago
Guys please help me ​
Likurg_2 [28]

Answer:

1)t=2.26\: s

2)S=33.9\: m

3)v=26.77\: m/s

4)\alpha=55.92

Explanation:

1)

We can use the following equation:

y_{f}=y_{0}+v_{iy}t-0.5*g*t^{2}

Here, the initial velocity in the y-direction is zero, the final y position is zero and the initial y position is 25 m.

0=25-0.5*9.81*t^{2}

t=2.26\: s

2)

The equation of the motion in the x-direction is:

v_{ix}=\frac{S}{t}

15=\frac{S}{2.26}

S=33.9\: m

3)

The velocity in the y-direction of the stone will be:

v_{fy}=v_{iy}-gt

v_{fy}=0-(9.81*2.26)

v_{fy}=-22.17\: m/s

Now, the velocity in the x-direction is 15 m/s then the velocity will be:

v=\sqrt{v_{x}^{2}+v_{fy}^{2}}=\sqrt{15^{2}+(-22.17)^{2}}

v=26.77\: m/s

4)

The angle of this velocity is:

tan(\alpha)=\frac{22.17}{15}

\alpha=tan^{-1}(\frac{22.17}{15})

\alpha=55.92

Then α=55.92° negative from the x-direction.

I hope it helps you!

6 0
3 years ago
Calculate the average speed in metres per second from Glasgow to Edinburgh
mariarad [96]
This is the same question as the one previously but with more details, so I will just use my previous answer.

1800 to 1820 is 20 minutes.1830 to 1838 is 8 minutes.1840 to 1905 is 25 minutes.
The total time travelled is 20+8+25 = 53 minutes = 3180 seconds.
The distance between Glasgow and Edinburgh is 28 + 12 + 34 = 74 km = 74000 m.

So, the average speed is 74000m/3180s = 23.27 m/s (4 s.f.)
5 0
2 years ago
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