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Rashid [163]
3 years ago
15

An x-ray beam of a certain wavelength is incident on a crystal, at 30.7° to a certain family of reflecting planes of spacing 33.

4 pm. If the reflection from those planes is of the first order, what is the wavelength of the x rays?
Physics
2 answers:
marissa [1.9K]3 years ago
4 0

Answer:

The wavelength of the x rays is 34.104 pm

Explanation:

Given data:

θ = incidence angle = 30.7°

d = space between planes = 33.4 pm = 33.4 x10⁻¹²m

According Bragg's expression:

n\lambda =2dsin\theta \\n=1,first-order\\\lambda =  2dsin\theta\\\lambda =2*33.4*sin30.7=34.104pm

klemol [59]3 years ago
3 0

Answer:

λ=34.068pm

Explanation:

Wavelength λ=2dsinθ

λ=2(33.4pm)sin30.7

λ=2(33.4pm) * 0.510

λ=66.8* sin30.7

λ=66.8*0.510

λ=34.068pm

X-rays are usually produced by charged particles that are accelerating or decelerating such as a beam of electrons striking a metal plate in an X-ray tube.

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A cable is 100-m long and has a cross-sectional area of 1.0 mm2. A 1000-N force is applied to stretch the cable. Young's modulus
Blizzard [7]

Answer:

1 m

Explanation:

L = 100 m

A = 1 mm^2 = 1 x 10^-6 m^2

Y = 1 x 10^11 N/m^2

F = 1000 N

Let the cable stretch be ΔL.

By the formula of Young's modulus

Y=\frac{F\times L}{A\times\Delta L}

\Delta L=\frac{F\times L}{A\times\Y}

\Delta L=\frac{1000\times 100}{10^{-6}\times10^{11}}

ΔL = 1 m

Thus, the cable stretches by 1 m.

4 0
3 years ago
he fan blades on a jet engine make one thousand revolutions in a time of 54.9 ms. What is the angular frequency of the blades?
Gnesinka [82]

So, the angular frequency of the blades approximately <u>36.43π rad/s</u>.

<h3>Introduction</h3>

Hi ! Here I will discuss about the angular frequency or what is also often called the angular velocity because it has the same unit dimensions. <u>Angular frequency occurs, when an object vibrates (either moving harmoniously / oscillating or moving in a circle)</u>. Angular frequency can be roughly interpreted as the magnitude of the change in angle (in units of rad) per unit time. So, based on this understanding, the angular frequency can be calculated using the equation :

\boxed{\sf{\bold{\omega = \frac{\theta}{t}}}}

With the following condition :

  • \sf{\omega} = angular frequency (rad/s)
  • \sf{\theta} = change of angle value (rad)
  • t = interval of the time (s)

<h3>Problem Solving</h3>

We know that :

  • \sf{\theta} = change of angle value = 1,000 revolution = 1,000 × 2π rad = 2,000π rad/s >> Remember 1 rev = 2π rad/s.
  • t = interval of the time = 54.9 s.

What was asked :

  • \sf{\omega} = angular frequency = ... rad/s

Step by step :

\sf{\omega = \frac{\theta}{t}}

\sf{\omega = \frac{2,000 \pi}{54.9}}

\boxed{\sf{\omega \approx 36.43 \pi \: rad/s}}

<h3>Conclusion :</h3>

So, the angular frequency of the blades approximately 36.43π rad/s.

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