Answer:
He traveled 22.5 meters during his acceleration
Explanation:
Jeremy is riding his bike down a straight road at 3 m/s when he
accelerates at a constant rate
⇒ His initial speed = 3 m/s
He accelerates at a constant rate for 5 seconds
⇒ The time of acceleration = 5 seconds
He reaches a speed of 6 m/s
⇒ His final speed = 6 m/s
We need to find how far he traveled during his acceleration
<em>Lets find his constant acceleration at first</em>
Acceleration is the rate of change in velocity
, where v is the final velocity , u is the initial velocity
and t is the time of acceleration
⇒
m/sec²
<em>Now lets find the distance using the rule</em> ![s=ut+\frac{1}{2}at^{2}](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E%7B2%7D)
where s is the distance
⇒ ![s=3(5)+\frac{1}{2}(0.6)(5)^{2}](https://tex.z-dn.net/?f=s%3D3%285%29%2B%5Cfrac%7B1%7D%7B2%7D%280.6%29%285%29%5E%7B2%7D)
⇒ s = 15 + 7.5 = 22.5
The distance is 22.5 meters
<em>He traveled 22.5 meters during his acceleration</em>