Answer:
Gravity
Explanation:
Gravity pulls things down to earth and it is a force
<span>Answer:
p[0] = 0
v[0] = 50 mi/h = 50 * 5280 / 3600 ft/s = 50 * (22/15) ft/s = 10 * 22/3 ft/s = 220/3 ft/s
a = -50 ft/s^2
a = -50
Integrate to find velocity
v = -50t + C
220/3 = -50 * 0 + C
220/3 = C
v = 220/3 - 50t
Find when v = 0
0 = 220/3 - 50 * t
50 * t = 220/3
t = 220 / 150
t = 22/15
Integrate the velocity function to find the position function
p = (220/3) * t - 25 * t^2 + C
0 = (220/3) * 0 - 25 * 0^2 + C
0 = C
p = (220/3) * t - 25 * t^2
t = 22/15
p = (220/3) * (22/15) - 25 * (484/225)
p = (4840 / 45) - 484 / 9
p = 484 * (10/45 - 1/9)
p = 484 * (2/9 - 1/9)
p = 484 * (1/9)
p = 484/9
p = 53.777777777777777777777777777778
53.8 feet</span>
The atomic mass. By taking two different types of the same element and calculating the average based on the amount of each type in the world, you get the basic atomic difference.
Answer:
10.05volts
Explanation:
Work done to move a charge from the positive side of a plate to the negative side is represented mathematically as 1/2CV² which is also the energy stored by the capacitor.
Work done = 1/2CV² where
C is the charge
V is voltage difference that exists between the plates.
Given Work done = 101Joules
C = 2Coulombs
Substituting the values in the formula to get V, we will have;
101 = 1/2(2)V²
101 = V²
V = √101
V = 10.05volts
Therefore the voltage difference between the plates is 10.05colt's
Answer:
F1= 196 N
F2= 392 N
Explanation:
Given:
length of the plank = 2 m
mass of the plank = 20 kg
Weight of the plank = 20 x 9.8 =196 N
Torque due to the weight of the plank with respect to the pivoted end (i.e the end held by the hand) Counter clockwise torque = 196 x cog of wood
= 196 x 1 = 196 Nm
Clockwise torque = F2 x 0.5
for the balanced case
F2 x 0.5 = 196
F2 = 196/ 0.5
F2= 392 N
now,
the net force
Net downward force =Net upward force
F1 + weight of plank = F2
F1 + 196 = 392N
F1 = 392 – 196
F1= 196 N