1. A scientist investigating the cell membrane concludes that a particular substance is transported
1 answer:
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Answer:
A) 0.82 g
B) 306 g
C) 0.23 g
D) g
E) 764 g
Explanation:
A) Upon consulting a periodic table one can find the atomic masses of each element present at a given molecule.
H=1.00 g/mol K=39.10 O=16.00
By adding the masses of the atoms in a molecule, we get its molecular weight.
KOH molecular mass is 1.00+39.10+16 = 56.10 g/mol
Therefore the mass in 0.0146 mol of KOH is:
56.10 g/mol x 0.0146 mol = 0.82 g
B) Upon consulting a periodic table one can find the atomic masses of each element present at a given molecule.
H=1.00 g/mol C=12.01
By adding the masses of the atoms in a molecule, we get its molecular weight.
C2H6 molecular mass is 6x1.00+2x12.01= 30.02 g/mol
Therefore the mass in 10.2 mol of KOH is:
30.02 g/mol x 10.2 mol = 306 g
C) Upon consulting a periodic table one can find the atomic masses of each element present at a given molecule.
Na=22.99 g/mol S=32.07 O=16.00
By adding the masses of the atoms in a molecule, we get its molecular weight.
Na2SO4 molecular mass is 2x22.99+32.07+4x16.00=142.05 g/mol
Therefore the mass in 0.0016 mol of Na2SO4 is:
142.05 g/mol x 0.0016 mol = 0.23 g
D) Upon consulting a periodic table one can find the atomic masses of each element present at a given molecule.
H=1.00 g/mol C=12.01 O=16.00
By adding the masses of the atoms in a molecule, we get its molecular weight.
C6H12O6 molecular mass is 16x1.00+6x12.01+6x16.00= 184.06 g/mol
Therefore the mass in 6854 mol of C6H12O6 is:
184.06 g/mol x 6854 mol = g
E) Upon consulting a periodic table one can find the atomic masses of each element present at a given molecule.
H=1.00 g/mol Cl=35.45 g/mol Co=58.93 g/mol N=14.01 g/mol
By adding the masses of the atoms in a molecule, we get its molecular weight.
Co(NH3)6 Cl3 molecular mass is 58.93+6x14.01+18x1.00+3x35.45=267.34 g/mol
Therefore the mass in 2.86 mol of Co(NH3)6 Cl3 is:
267.34 g/mol x 2.86 mol = 764 g