Answer:
<em>The crane lifts the crate up to 76 m high</em>
Explanation:
<u>Work Done by a Force</u>
The work done by a force of magnitude F that displaces an object by a distance y is given by
We know a crane does a work of 9,500 Joule to lift a crate and is using a force of 125 Nw.
The above equation can be solved to know the value of y in terms of the work and the force:
Plugging in the given values
The crane lifts the crate up to 76 m high
Based on the forces acting on the axes, the resultant moments will be (345, 400, 600 N·m)
<h3>What would be resultant moment about x-axis?</h3>= F₃ x 3
= -115 x 3
= -345 N·m
<h3>What would be resultant moment about y-axis?</h3>= F₁ x 2
= -200 x 2
= -400 N·m
<h3>What would be the resultant moment about z-axis?</h3>= F₄ x 2
= -300 x 2
= - 600 N·m
In conclusion, the resultant moment about x, y, and z axes is (345, 400, 600 N·m)
Find out more on resultant moments at brainly.com/question/6278006.
Explanation:
Given:
Solving for :
where:
Integrating to get with initial conditions
:
Integrating to get x with initial conditions x(0) = 0:
When t=T:
Answer: Got It!
<em>Explanation: </em>let s = speed at launch
v = 0 at top = s sin 63 - g t
so at top
t = s sin 63/g = .0909 s
h = 13.6 = s sin 63 t - 4.9 t^2
13.6 = .081s^2 - .0405 s^2
s^2 = 336
s = 18.3 m/s
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