Question

Calculate the bond energy of HBr.Bond energy of H2 is 436KJ/mol and that of Br2 is 193KJ/mol.

Answer 1

Answer:

ΔH3 =  1/2 (629) - ΔH^0

Explanation:

Given data:

Bond energy of H2 = ΔH1 =  436 Kj/mol

Bond energy of Br2 = ΔH2 = 193 Kj/mol

To find:

Let bond energy of HBr = ΔH3 = ?

Equation:

H2 + Br2 → 2HBr

enthalpy of formation of HBr = ΔH1 + ΔH3 - 2(ΔH3)

ΔH^0 = 436 + 193 -   2(ΔH3)

(436 + 193) - ΔH^0 = 2(ΔH3)

ΔH3 =  1/2 (629) - ΔH^0