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nydimaria [60]
2 years ago
5

If the torque required to loosen a nut that

Physics
1 answer:
liraira [26]2 years ago
7 0

Explanation:

τ = Fr

34 Nm = F (0.30 m)

F ≈ 113 N

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A 650 kg steel beam is being pulled up by a crane with a force of 7020 N. What is the upwards acceleration of the beam?
zimovet [89]

Answer: 1 m/s^2

Explanation:

n= w+ma

n= Mg+Ma

7020 = (650)(9.8)+650a

7020 = 6370+ 650a

650=650a

A= 1 m/s^2

8 0
3 years ago
A block slides down a frictionless incline with constant acceleration. After sliding 6.80 m down, it has a speed of 3.80 m/s. Wh
melisa1 [442]

Answer:

speed when the block had slid 3.40 m is 2.68 m/s

Explanation:

given data

distance = 6.80 m

speed = 3.80 m/s

to find out

speed when the block had slid 3.40 m

solution

we will apply here equation of motion that is

v²-u² = 2×a×s   ..............1

here s is distance, a is acceleration and v is speed and u is initial speed that is 0

so put here all value in equation 1 to get a

v²-u² = 2×a×s

3.80²-0 = 2×a×6.80

a = 1.06 m/s²

so

speed when distance 3.40 m

from equation 1 put value

v²-u² = 2×a×s

v²-0 = 2×1.06×3.40

v² = 7.208

v = 2.68

so speed when the block had slid 3.40 m is 2.68 m/s

7 0
3 years ago
A waiter is carrying a tray above his head and walking at a constant velocity. If he applies a force of 5.0 newtons on the tray
k0ka [10]
W = f × x = 5 × 10 = 50
4 0
2 years ago
Read 2 more answers
An air-filled capacitor consists of twoparallel plates, each with an area of 7.60 cm2,separated by a distance of 1.90 mm.A 16.0
Svetradugi [14.3K]

Answer:

(A)8,421.1 V/m

(B) 3.54 x 10^{-12} F

(C)  53.1 x 10^{-12} C

(D)  6.987 x 10^{-8} C/m^{2}

Explanation:

area (A) = 7.6 cm^{2} = 0.00076 m^{2}

distance (d) = 1.9 mm = 0.0019 m

potential difference (v) = 16 V

(A) electric field (E) = Δv / d = 16 / 0.0019 = 8,421.1 V/m

(B)  capacitance = (∈₀A)/d

     where ∈₀ =  permitivity of free space = 8.85 x 10^{-12}m^{-3}.kg^{-1} .s^{4}.A^{2}

capacitance = \frac{8.85 x 10^{-12}x0.00076}{0.0019}

capacitance (C) = 3.54 x 10^{-12} F

(C) charge (q) = C x v =  3.54 x 10^{-12} x 16  = 56.64x 10^{-12} C

(D) surface charge density = charge (q) / area =   56.64 x 10^{-12}  / 0.00076  =  7.453 x 10^{-8} C/m^{2}

3 0
3 years ago
To understand the relationships among the parameters that characterize a wave. It is of fundamental importance in many areas of
34kurt

Answer:

The correct option is (c) "periodic wave"

Explanation:

The relationship between the angular frequency and the radial frequency is :

\omega=2\pi f

f is the radial frequency

Frequency, wavelength, velocity of propagation, and related variables do not depend on the amplitude of wave. Travelling waves are also known as periodic wave if their waveform repeats every time interval T. Frequency, wavelength and the speed of wave are the factors that defines traveling waves.

So, the correct option is (c) "periodic wave".

3 0
2 years ago
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