Answer:
The number of turns in secondary coil is 4000
Explanation:
Given:
Current in primary coil
A
Current in secondary coil
A
Number of turns in primary coil 
In case of transformer the relation between current and number of turns is given by,

For finding number of turns in secondary coil,



Therefore, the number of turns in secondary coil is 4000
Answer:

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Explanation:
I just answer the second question
Recall this kinematic equation:
a = 
This equation gives the acceleration of the object assuming it IS constant (the velocity changes at a uniform rate).
a is the acceleration.
Vi is the initial velocity.
Vf is the final velocity.
Δt is the amount of elapsed time.
Given values:
Vi = 0 m/s (the car starts at rest).
Vf = 25 m/s.
Δt = 10 s
Substitute the terms in the equation with the given values and solve for a:
a = 
<h3>a = 2.5 m/s²</h3>
Answer:
1440 × 10⁴ N/C
Explanation:
Data provided in the question:
Charge density λ1 = 0.6 μC/cm = 6 × 10⁻⁵ C/m
a = 7.5 cm = 0.075 m
Now,
Electric field due to a line charge at a distance 'a' is given as:
Ex(P) = 
also,
we know
= 9 × 10⁹ Nm²/C²
Thus,
we have
Ex(P) = 
therefore,
Ex(P) = 
= 1440 × 10⁴ N/C