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Nat2105 [25]
3 years ago
9

Which of the following devices would you expect to consume the most energy for each hour that it operates?

Physics
1 answer:
adelina 88 [10]3 years ago
7 0
What are the devices I don’t see any on there
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What is used as evidence for sea-floor spreading?
raketka [301]

Answer:

Sea-floor spreading occurs in the oceanic ridges. In there, volcanic activity, together with the gradual movement of the bottom, form new oceanic crust. This allows a better understanding of the continental drift explained by the theory of plate tectonics.

The greatest evidence for Sea-floor spreading is the oceanic trenches, the oceanic ridges, the magma protruding to the surface and the new seafloor.

In previous theories,  continents were assumed to be transported across the sea. Harry Hess, in the 1960s, proposed the idea that the seabed itself moves  as it expands from a central point. The theory is now accepted, and the phenomenon is thought to be caused by convection currents in the upper layer of the mantle.

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4 years ago
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Inert gas used to make bright city lights True or False
gogolik [260]

the answer is true because i think its true not 100 percent sure

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3 years ago
What kind of engine do most cars use today
Nadusha1986 [10]

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4 stroke 4 cylinder Natural Aspirated Gasoline engine

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im not 100%  sure

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3 years ago
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Examine the following circuit diagrams. In which diagram will current flow through one resistor?
Hoochie [10]

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4 0
4 years ago
A proton moves through a magnetic field at 26.7 % 26.7% of the speed of light. At a location where the field has a magnitude of
iogann1982 [59]

Answer:

8.64283\times 10^{-14}\ N

Explanation:

q = Charge of proton = 1.6\times 10^{-19}\ C

v = Velocity of proton = 0.267\times c

c = Speed of light = 3\times 10^8\ m/s

B = Magnetic field = 0.00687 T

\theta = Angle = 101^{\circ}

Magnetic force is given by

F=qvBsin\theta\\\Rightarrow F=1.6\times 10^{-19}\times (0.267\times 3\times 10^8)\times 0.00687\times sin101\\\Rightarrow F=8.64283\times 10^{-14}\ N

The magnetic force acting on the proton is 8.64283\times 10^{-14}\ N

4 0
4 years ago
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