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Valentin [98]
3 years ago
5

Which of the following best describes the relationship between water conservation and sanitation techniques?

Physics
1 answer:
vovikov84 [41]3 years ago
4 0
<span>The forth I think, conserving water is useless if it is just going to be contaminated in unsanitary conditons
</span>
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Which of the following is a disadvantage of radio?
Ne4ueva [31]

Answer:

option c

Explanation:

The disadvantage of the radio signal is option c) which is radio waves create electrical interference. The radio-wave interference also called as electromagnetic interference is the phenomena that occurs due to the radio waves. This phenomena affects the electric circuits. The effects includes the electromagnetic induction, conduction or electrostatic coupling.

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3 years ago
At the end of photosynthesis, what does the plant do with OXYGEN?
Naya [18.7K]

Its A

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Pendulum clocks are made to run at the correct rate by adjusting the pendulum’s length. Suppose you move from one city to anothe
levacccp [35]

Answer:

Obviously Lengthen...   T = 2\pi \sqrt{L/g}   or   g = 4\pi ^{2} L/g

Explanation:

As we can observe from the equation, time period of a simple pendulum depends upon the length directly. When the gravitational acceleration increases the time period of the pendulum decreases and vice versa. So, by increasing the length, the time period can be adjusted...

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3 years ago
The acceleration of an object would increase if there was an increase in:
kolezko [41]

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Its either B or A

Explanation:

6 0
3 years ago
A young kid of mass m = 36 kg is swinging on a swing. The length from the top of the swing set to the seat is L = 3.5 m. The boy
lara31 [8.8K]

Answer:

Explanation:

Given

mass of boy=36 kg

length of swing=3.5 m

Let T be the tension in the swing

At top point mg-T=\frac{mv^2}{r}

where v=velocity needed to complete circular path

Th-resold velocity is given by mg-0=\frac{mv^2}{r}

v=\sqrt{gr}=\sqrt{9.8\times 3.5}=5.85 m/s

So apparent weight of boy will be zero at top when it travels with a velocity of v=\sqrt{gr}

To get the velocity at bottom conserve energy at Top and bottom

At top E_T=mg\times 2L+\frac{mv^2}{2}

Energy at Bottom E_b=\frac{mv_0^2}{2}

Comparing two as energy is conserved

v_0^2=4gl+gl

v_0^2=5gL

v_0=\sqrt{5gL}=13.09 m/s

Apparent weight at bottom is given by

W=\frac{mv_0^2}{L}-mg=\frac{36\times 13.09^2}{3.5}+36\times 9.8=2115.23 N

6 0
3 years ago
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