Answer:
mlf=0.5038kg/s
Explanation:
a. Please kindly check attachment for the step by step solution
b. B) in concurrent flow heat exchanger same exit temperatures for both fluids cannot be obtained. Since tho<tco
Case ii) only liquid food is considered tci=20 &tco=80
Cp=3.9kj/kgk
&If Q is same then mlf=0.5038kg/s this is same as case a
Answer:
h_f = 15 ft, so option A is correct
Explanation:
The formula for head loss is given by;
h_f = [10.44•L•Q^(1.85)]/(C^(1.85))•D^(4.8655))
Where;
h_f is head loss due to friction in ft
L is length of pipe in ft
Q is flow rate of water in gpm
C is hazen Williams constant
D is diameter of pipe in inches
We are given;
L = 1,800 ft
Q = 600 gpm
C = 120
D = 8 inches
So, plugging in these values into the equation, we have;
h_f = [10.44*1800*600^(1.85)]/(120^(1.85))*8^(4.8655))
h_f = 14.896 ft.
So, h_f is approximately 15 ft
Answer:
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