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morpeh [17]
3 years ago
5

In a solution of salt and water, if the concentration of salt molecules is greater outside a cell than inside, then water molecu

les will __________. . . . . . . . . . A. . move into the cell, and the cell will shrivel . . . . . . . . B. . move into the cell, and the cell will burst . . . . . . . . C. . move out of the cell, and the cell will shrivel . . . . . . . . D. . move out of the cell, and the cell will burst .
Chemistry
1 answer:
Katarina [22]3 years ago
4 0
The movement of salt molecules in a system and surroundings that have different concentrations follow the osmosis principle. Osmosis is the phenomena where molecules move from lower concentration to higher concentration through a sem-permeable membrane. when the concentration is higher outside, then answer is C. molecules <span>move out of the cell, and the cell will shrink or shrivel.</span>
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If the oxidation number of an atom decreases, the atom has undergone oxidation.
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Oxidation is a process when an atom, a group of atoms, or an ion loses electrons.

For example,

Cu⁰ -------> Cu⁺² + 2e⁻. This is an oxidation process.

As we can see an oxidation number was 0, and it became +2. The oxidation number is increased. Oxidation number of the atom, when an atom has undergone oxidation, increases.

So, answer is b.False.

8 0
3 years ago
When lewis structures are drawn, do you only show valence electrons??
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3 years ago
Determine the free energy(ΔG) from the standard cell potential (Ecell0 ) for the reaction:2ClO2-(aq)+Cl2(g)→2ClO2(g)+ 2Cl-(aq)wh
Dima020 [189]

<u>Answer:</u> The \Delta G^o for the given reaction is -7.84\times 10^4J

<u>Explanation:</u>

For the given chemical reaction:

2ClO_2^-(aq.)+Cl_2(g)\rightarrow 2ClO_2(g)+2Cl^-(aq.)

Half reactions for the given cell follows:

<u>Oxidation half reaction:</u> ClO_2^-\rightarrow ClO_2+e^-;E^o_{ClO_2^-/ClO_2}=0.954V  ( × 2)

<u>Reduction half reaction:</u> Cl_2+2e^-\rightarrow 2Cl(g);E^o_{Cl_2/2Cl^-}=1.36V

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=1.36-(0.954)=0.406V

To calculate standard Gibbs free energy, we use the equation:

\Delta G^o=-nFE^o_{cell}

Where,

n = number of electrons transferred = 2

F = Faradays constant = 96500 C

E^o_{cell} = standard cell potential = 0.406 V

Putting values in above equation, we get:

\Delta G^o=-2\times 96500\times 0.406=-78358J=-7.84\times 10^4J

Hence, the \Delta G^o for the given reaction is -7.84\times 10^4J

4 0
3 years ago
N2 + 3 H2 – 2 NH3 How many moles of nitrogen (N2) are required to get 6
Iteru [2.4K]

Answer:

N2 + 3H2 → 2NH3. 14 moles a. If 6 mol of H2 are consumed, how many moles of NH3 are produced? ... a 3 mol H₂. 4. How many moles of nitrogen are needed to make 11 moles of NH3? Il mol NH₃ x Imol Na = 15.5

5 0
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Which type of society survives mainly by foraging for food?
Dennis_Churaev [7]
The appropriate answer is a. HUNTER-GATHERER. Hunter-gatherer societies are nomadic and they forage for edible plants, bean, fruits and nuts. They also hunt wild game for food. Early humans in the Neolithic period practiced this way of life. 
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