1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
3241004551 [841]
3 years ago
9

A 3500 kg spaceship is in a circular orbit 220 km above the surface of Earth. It needs to be moved into a higher orbit of 360 km

to link up with the space station at that altitude. In this problem you can take the mass of the Earth to be (5.97 * 10^24)a) How much work, in joules, do the spaceship’s engines have to perform to move to the higher orbit? Ignore any change of mass due to fuel consumption?
Physics
1 answer:
Vitek1552 [10]3 years ago
7 0

Answer:

The work done is calculated as 0.044\times 10^{11}\ J

Solution:

As per the question:

Mass of the spaceship, m = 3500 kg

Height of the orbit, h = 220 km

Mass of the earth, M_{e} = 5.97\times 10^{24}\ kg

Height of the higher orbit, h' = 360 km

Radius of the orbit, R = 6.37\times 10^{6}\ km

Now,

The work done is given by the change in the gravitational potential energy:

Gravitational Potential Energy, U = - \frac{GM_{e}m}{R + h}

Now, for the lower orbit:

U_{l} = - \frac{GM_{e}m}{R + h}

U_{l} = - \frac{6.67\times 10^{- 11}\times 5.97\times 10^{24}\times 3500}{6.37\times 10^{6} + 220\times 10^{3}}

U_{l} = - 2.115\times 10^{11}\ J

For upper orbit:

U_{U} = - \frac{GM_{e}m}{R + h}

U_{u} = - \frac{6.67\times 10^{- 11}\times 5.97\times 10^{24}\times 3500}{6.37\times 10^{6} + 360\times 10^{3}}

U_{U} = - 2.071\times 10^{11}\ J

Change in the gravitational Potential energy:

\Delta U = U_{U} - U_{l} = - 2.071\times 10^{11} - (- 2.115\times 10^{11}) = 0.044\times 10^{11}\ J

Therefore, the work done:

W = 0.044\times 10^{11}\ J

You might be interested in
which statements about velocity are true? check all that apply. a. for velocity, you must have a number, a unit, and a direction
satela [25.4K]
a). for velocity, you must have a number, a unit, and a direction.
Yes.  This one isn't bad.  The 'number' and the 'unit' are the speed.

b). the si units for velocity are miles per hour.
No.  That's silly. 
'miles' is not an SI unit, and 'miles per hour'
is only a speed, not a velocity. 

c). the symbol for velocity is .
You can use any symbol you want for velocity, as long as
you make its meaning very clear, so that everybody knows
what symbol you're using for velocity.
But this choice-c is still wrong, because either it's incomplete,
or else it's using 'space' for velocity, which is a very poor symbol.

d). to calculate velocity, divide the displacement by time.
Yes, that's OK, but you have to remember that the displacement
has a direction, and so does the velocity.
3 0
3 years ago
‏A 50 - N x m torque acts on a wheel with a moment of inertia 150 kg x m² . If the wheel starts from rest , how long will it tak
denis-greek [22]

Answer:

t = 6.17 s

Explanation:

For a 1 revolution movement, \triangle \theta = 2\pi

Torque, \tau = 50 Nm

Moment of Inertia, I = 150 kg m^2

If the wheel starts from rest, w_{0} = 0 rad/s

The angular displacement of the wheel can be given by the formula:

\triangle \theta = \omega_0 t + 0.5 \alpha t^2................(1)

Where \alpha is the angular acceleration

\tau = I \alpha\\\alpha = \frac{\tau}{I} \\\alpha = 50/150\\\alpha = 0.33 rad/s^2

To get t, put all necessary parameters into equation (1)

2\pi = 0(t) + 0.5(0.33)t^2\\2\pi =0.5(0.33)t^2\\t^2 = \frac{4 \pi}{0.33} \\t^2 = 38.08\\t = 6.17 s

3 0
3 years ago
If an object is not accelerating what can you determine about the sum of all the forces on the object
xxTIMURxx [149]
If object is not accelerating, the sum of all forces on the object will be equal to ZERO...
8 0
3 years ago
A horizontal spring is attached to a wall at one end and a mass at the other. The mass rests on a frictionless surface. You pull
LenKa [72]

Answer:

54%

Explanation:

So, we have that the "magnitude of its displacement from equilibrium is greater than (0.66)A—''. Thus, the first step to take in answering this question is to write out the equation showing the displacement in simple harmonic motion which is = A cos w×t.

Therefore, we will have two instances t the displacement that is to say at a point 2π/w - a2 and the second point at a = a2.

Let us say that 2π/w = A, then, we have that a = A cos ^-1 (0.66)/2π. Also, we have that a2 = A/2 - A cos^- (0.66) / 2π.

The next thing to do is to calculate or determine the total length of of the required time. Thus, the total length is given as:

2a1 + ( A - 2a2) = 2A{ cos^-1 (0.66)}/ π.

Therefore, the total percentage of the period does the mass lie in these regions = 100 × {2a1 + ( A - 2a2) }/A = 2 { cos^-1 (0.66)}/ π × 100 = 54%.

Thus, the total percentage of the period does the mass lie in these regions = 54%.

6 0
3 years ago
Calculate the work done in moving a charge of 2 coulombs across 2 points having a potential difference of 12 volts
Veseljchak [2.6K]

Answer:

Work is done in moving a charge of 2 coulomb across two points having a potential difference of 12 volt is 24 joule .

Explanation:

8 0
3 years ago
Other questions:
  • Is "A firecracker that has not been lit kinetic, or potential energy?
    14·1 answer
  • CH, +20, → CO2 + 2H,0<br> CH, +20, are the<br> of the above chemical reaction.
    11·1 answer
  • The climate of a location is affected by the presence of
    6·2 answers
  • Can someone please here me I’m confused
    9·1 answer
  • It is known that a certain kind of algae in the Dead Sea can double in population every 2 days. Suppose that the population of a
    14·1 answer
  • The human eye can readily detect wavelengths from about 400 nm to 700 nm. part a if white light illuminates a diffraction gratin
    10·1 answer
  • Determine the dimensions (a, b) of an air-filled rectangular waveguide that providessingle mode operation over the frequency ran
    13·1 answer
  • If a car with an initial velocity of 10 m/s accelerates at a rate of 50 m/s^2
    12·1 answer
  • Una carga eléctrica de 120 Coulomb pasa uniformemente por la sección transversal de un hilo conductor durante un minuto. La inte
    9·1 answer
  • so i had to work for halloween, my first Halloween working. When i got home my lil bro showed me all the candy he collected so i
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!