The magnitude of v⃗ is {sqrt(m1v1)2+(m2v2)2/ m1+m2}, that is, the speed v of the two-car unit after the collision.
<h3>What is
collision?</h3>
- In physics, collisions occur when particles, aggregates of particles, or solids come close to each other, interact and affect each other.
- Collisions are of three types Fully elastic collision, inelastic collision and Perfectly inelastic collision.
- Multiply the mass of the second object by its velocity.
- For example, if the weight is 1,000 and the speed is -30 meters per second, then its momentum is 30,000 kg meters per second.
- Add the two velocities together to determine the direction the object will move after a collision.
- So the formula for determining the size of a vector (in 2D space) is v = (x, y).|v| = √(x2 + y2).
- This formula is derived from the Pythagorean theorem.
- The formula V = (x, y, z) that determines the size of a vector (in 3-dimensional space) is:|V| = √(x2 + y2 + z2)
To learn more about collision from the given link :
brainly.com/question/13138178
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The correct
answer between all the choices given is the second choice or letter B. I am
hoping that this answer has satisfied your query and it will be able to help
you in your endeavor, and if you would like, feel free to ask another question.
The solution would
be like this for this specific problem:
<span>M=<span>P/V</span></span>
<span>M=<span>8/10</span></span>
<span><span>M=0.8</span></span>
Answer:
Explanation:
m = 0.5 kg
A = 0.15 m
vmax = 1.25 m/s
vmax = ω x A
1.25 = ω x 0.15
ω = 8.33 rad/s
(a) Let the spring constant be k
k = ω² m = 8.33 x 8.33 x 0.5 = 34.7 N/m
(b) Maximum acceleration, a max = ω² A = 8.33 x 8.33 x 0.15 = 10.42 m/s^2
(c) Let f be the frequency
ω = 2 π f
8.33 = 2 x 3.14 x f
f = 1.326 Hz
(d) Total energy
E = 1 /2 m x ω² x A² = 0.5 x 0.5 x 8.33 x 8.33 x 0.15 x 0.15 = 0.39 J
Answer:
a= (-g) from the moment the ball is thrown, until it stops in the air.
a = (0) when the ball stops in the air.
a = (g) since the ball starts to fall.
Explanation:
The acceleration is <em>(-g)</em> <em>from the moment the ball is thrown, until it stops in the air</em> because the movement goes in the opposite direction to the force of gravity. In the instant <em>when the ball stops in the air the acceleration is </em><em>(0)</em> because it temporarily stops moving. Then, <em>since the ball starts to fall, the acceleration is </em><em>(g)</em><em> </em>because the movement goes in the same direction of the force of gravity