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timofeeve [1]
3 years ago
8

Suppose that an owner of the same dog breed has also taken some measurements. They notice that the surface area of the dog has i

ncreased by a factor of 3 over a period of four years. Determine the change in the dog's relative surface area in this time period.
Physics
1 answer:
Mnenie [13.5K]3 years ago
7 0

Answer:

Surface area of the dog is changes from A to 3A

Explanation:

It is given that surface area of dog is increased by factor 3 in a period of 4 year

We have to find the change in dog's relative surface area in the given time period

Let initially the surface area is A

As the surface area is increased by a factor of 3

So surface area after 4 year = 3×A = 3A

So surface area of the dog is changes from A to 3A

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Where are volcanoes located(in terms of the plates)?
taurus [48]

Most volcanoes are found at convergent or divergent plate boundaries, but intraplate volcanoes are found in the middle of a tectonic plate.

4 0
4 years ago
One liter (1000cm3) of oil is spilled onto a smooth lake. If the oil spreads out uniformly until it makes an oil slick just one
Zepler [3.9K]

Answer:

he diameter of the oil slick is 2523 m

Explanation:

given information?

V = 1 L = 1000 cm³ = 0.001 m³

h = 2 x 10⁻¹⁰ m

first we have to find the radius using the following equation

V = πr²h

r = √V/(πh)

  = √(0.001)/(π x 2 x 10⁻¹⁰ )

  = 1261.56 m

now, we can calculate the diameter of the oil slick

d = 2r

  = 2 (1261.56)

  = 2523 m

8 0
3 years ago
Two closed organ pipe gives 4 beats when sounded together at 5°C. Calculate the number of beats in 35°C​
Gre4nikov [31]

Answer:

The number of beats is 10.58 in 35°C.

Explanation:

The beat frequency is given by : f₁-f₂

At 5°C, f₁-f₂ = 4

We need to find the number of beats in 35°C​.

The frequency in a standing wave is proportional to \sqrt T.

So,

\dfrac{f_1-f_2}{f_1'-f_2'}=\dfrac{\sqrt {T}}{\sqrt{T'}}\\\\f_1'-f_2'=(f_1-f_2)\times \dfrac{\sqrt{T'}}{\sqrt{T}}\\\\f_1'-f_2'=4\times \dfrac{\sqrt{35}}{\sqrt{5}}\\\\f_1'-f_2'=10.58

So, the number of beats is 10.58 in 35°C.

7 0
3 years ago
A flash light has a potential difference of 6 volts and a resistor of 2 Ohms . The current in the flash light is
Vlada [557]

Answer:

3 amps

Explanation:

Volts divided by ohms

3 0
3 years ago
What minimum speed must an electron have to excite the 492-nm-wavelength blue emission line in the hg spectrum?
mezya [45]
The energy required by the excitation of the line is:
ΔE = hν = hc / λ
where:
ΔE = energy difference
h = Planck constant 
ν = line frequency
c = speed of light
λ = line wavelength

The energy difference must be supplied by the electron, supposing it transfers all its kinetic energy to excite the line:
\Delta E =  \frac{1}{2} m v^{2}

Therefore, 
\frac{1}{2} m v^{2} =  \frac{hc}{\lambda}

And solving for v we get:
v =  \sqrt{ \frac{2hc}{m\lambda} }

Plugging in numbers (after trasforing into the correct SI units of measurement):
v = \sqrt{ \frac{(2)(6.6 \cdot  10^{-34})(3 \cdot  10^{8})  }{(9.11 \cdot  10^{-31})(4.92 \cdot  10^{-7}) } }
=9.4 · 10⁵ m/s

Hence, the electron must have a speed of 9.4 · 10<span>⁵ m/s in order to excite the <span>492nm</span> line.</span>
5 0
3 years ago
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