Answer:
A series circuit has a direct flow of current and because of that, the current is constant throughout the circuit, while the voltage is what changes.. In a parallel circuit, the current travels through multiple paths, so the current is divided among those paths. The voltage, on the other hand, is constant.
Explanation:
Definition of series and parallel circuits.
brainliest please <3
Answer:
-7.14
Explanation:
According to equation of motion
v = u + at
where
v is the final velocity at any time t
u is the initial velocity
a is the acceleration
and t is the time
___________________________________________
Given
An object is thrown upward it means
its initial velocity is in upward direction
but acceleration due to gravity is in downward direction which will cause to decrease the velocity of object.
Intial velocity u = 31.1 m/s
final velocity v at 4 second we have to find.
t = 4 second
a = g = 9.81 m/s2 (it is acting in opposite direction of motion hence its sign will be negative ).
Thus
a = - 9.81 m/s2
using the above values in v = u + at
v = 32.1 - 9.81*4
v = 32.1 - 39.24
v = -7.14
Thus, correct option is -7.14.
I' m going to say B. WHAT SUBSTANCES MAKE UP AN EGGSHELL?
You have to look at keywords here, and the only one that refers to scientific research would be Substance.
The density of the metal cube is 2.703 g/cm³.
The mass of a metal cube is m =50.3 grams.
The edge length of the metal cube is l = 2.65 cm.
Now, the density (ρ) of a cube can be given as:
ρ = m/(a)³
Where (a)³ is the volume of the cube, m is the mass of the cube, ρ is the density of the cube, and a is the length of one side of the cube.
Since the sides of a cube are equal therefore the value of a is the same for each edge length of the cube.
Now, the density of the metal cube in g/cm³ is:
ρ = m / a³
ρ = m / l³
ρ = 50.3 g / (2.65 cm)³
ρ = 50.3 g / (2.65 cm)(2.65 cm)(2.65 cm)
ρ = 50.3 g / 18.609 cm³
ρ = 2.703 g/cm³
Learn more about density here:
brainly.com/question/1354972
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The area of the rectangle plus the area of the triangle under the line .-.
