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elena-s [515]
3 years ago
12

A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 500 V . The rat

e at which electrical energy is dissipated in the resistor is 296 W Part A
What is the impedance Z of the circuit?
Express your answer to three significant figures and include the appropriate units.
Part B
What is the amplitude of the voltage across the inductor?
Express your answer to three significant figures and include the appropriate units
Part C
What is the power factor?
Express your answer using three significant figures.
Physics
1 answer:
max2010maxim [7]3 years ago
6 0

Answer:

Explanation:

 Rate of dissipation of energy at resistor

= I² R = 296

current I² = 296/R = 296 / 300

I = 0.9933 A.

Impedence Z = V / I = 500 / .9933

= 503 ohm.

B ) Let it be V

voltage across resistance = 300 x .9933 = 298 v

Now 500² = 298² + V²

V = 401 v

C)  Power factor = R / Z

=300 / 503

= 0.596

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A camera lens with focal length f = 50 mm and maximum aperture f>2
Brut [27]

Answer:

The minimum distance between two points on the  object that are barely resolved is 0.26 mm

The corresponding distance between the  image points = 0.0015 m

Explanation:

Given  

focal length f = 50 mm and maximum aperture f>2

s =  9.0 m

aperture = 25 mm = 25 *10^-3 m

Sin a = 1.22 *wavelength /D  

Substituting the given values, we get –  

Sin a = 1.22 *600 *10^-9 m /25 *10^-3 m

Sin a = 2.93 * 10 ^-5 rad

Now  

Y/9.0 m = 2.93 * 10 ^-5

Y = 2.64 *10^-4 m = 0.26 mm

Y’/50 *10^-3 = 2.93 * 10 ^-5  

Y’ = 0.0015 m

8 0
3 years ago
If an object is thrown upward with an initial velocity of 128 ​ft/second, then its height after t seconds is given by the follow
IrinaK [193]

Answer:

The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.

Explanation:

Given that,

Initial velocity u= 128 ft/sec

Equation of height

h = 128t-32t^2....(I)

(a). We need to calculate the maximum height

Firstly we need to calculate the time

\dfrac{dh}{dt}=0

From equation (I)

\dfrac{dh}{dt}=128-64t

128-64t=0

t=\dfrac{128}{64}

t=2\ sec

Now, for maximum height

Put the value of t in equation (I)

h =128\times2-32\times4

h=128\ ft

(b). The number of seconds it takes the object to hit the ground.

We know that, when the object reaches ground the height becomes zero

128t-32t^2=0

t(128-32t)=0

128=32t

t=4\ sec

Hence, The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.

3 0
3 years ago
the cycle of the moon through its phases, or the synodic month, is a. 21 days long. b. 27 1/3 days long. c. 29 1/2 days long. d.
olasank [31]
It takes 29.5 days long
7 0
3 years ago
What is the ability to complete extended periods of physical activity?
gogolik [260]
Endurance is the ability to complete extended periods of physical activity
8 0
3 years ago
Read 2 more answers
Over 4 seconds, a car's momentum decreases by 1000 kg m/s how much force did it take to make this happen?
kotykmax [81]

Answer:

250N

Explanation:

Given parameters:

Time  = 4s

Momentum  = 1000kgm/s

Unknown:

Force  = ?

Solution:

To solve this problem, we use Newton's second law of motion;

      Ft  = Momentum

F is the force

t is the time

So;

          F x 4 = 1000kgm/s

          F  = 250N

6 0
2 years ago
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