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gulaghasi [49]
3 years ago
10

In a hydrochloric acid solution, where the [HCl] is 0.010 M, what is the pH?

Chemistry
1 answer:
Alex Ar [27]3 years ago
6 0

Answer:

pH = 2.0

Explanation:

the pH of the strong HCl acid solution will be

pH = -log[H+] = -log[0.010] =  2

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Suppose of potassium sulfate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of potassium
dimulka [17.4K]

Answer:

This question is incomplete, here's the complete question:

<em><u>"Suppose 0.0842g of potassium sulfate is dissolved in 50.mL of a 52.0mM aqueous solution of sodium chromate. Calculate the final molarity of potassium cation in the solution. You can assume the volume of the solution doesn't change when the potassium sulfate is dissolved in it. Round your answer to 2 significant digits."</u></em>

Explanation:

Reaction :-

K2SO4 + Na2CrO4 ------> K2CrO4 + Na2SO4

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0.000483 mol of K2CrO4 will dissociate into 2* 0.000483 mol of K^+

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= (2*0.000483 mol) / 0.05 L = 0.02 mol/L = 0.02 M

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