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3 years ago

: Absolute uncertainties are added in which following operations

Physics

1 answer:

goldfiish [28.3K]3 years ago

7 0

Answer:

Answer B (I & II)

Explanation:

Absolute uncertainties are added in the case of addition and subtraction. Therefore, the correct answer is answer B (I & II)

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Which are properties of both a gas and a plasma

viktelen [127]

A plasma is an ionized gas , a gas into which sufficient energy is provided to free electrons from atoms or molecules and to allow both species , ions and electrons to coexist , Gases can become plasma in several ways , but all include pumping the gas with energy,

8 0

3 years ago

Read 2 more answers

For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The larg

DIA [1.3K]

The given question is incomplete. The complete question is as follows.

For your senior project, you would like to build a cyclotron that will accelerate protons to 10% of the speed of light. The largest vacuum chamber you can find is 60 cm in diameter.

What magnetic field strength will you need?

Explanation:

Formula for the strength of magnetic field is as follows.

B = $\frac{mv}{qr}$

Here, m = mass of proton = $1.67 \times 10^{-27}$ kg

v = velocity = 10% of $3 \times 10^{8}$ = $3 \times 10^{7}$ m/s

q = charge of proton = $1.6 \times 10^{-19} C$

r = radius = $\frac{60}{2}$ = 30 cm = 0.30 m (as 1 m = 100 cm)

Therefore, magnetic field will be calculated as follows.

B = $\frac{mv}{qr}$

= $\frac{1.67 \times 10^{-27} \times 3 \times 10^{7}}{1.6 \times 10^{-19} C \times 0.30 m}$

= $\frac{5.01 \times 10^{-20}}{0.48 \times 10^{-19}}$

= 1.0437 T

Thus, we can conclude that magnetic field strength is 1.0437 T.

7 0

4 years ago

7. Calculate the force applied on an object if the Pressure exerted is 90 Pascal over an area of 900 cm2.

Tanya [424]

Answer:

Explanation: pressure = force / area

Rearrange to get: force = pressure x area. 900 cm2 = 0.09 m2

force = 90 x 0.09

= 8.1 N

6 0

3 years ago

The closely packed cones in the fovea of the eye have a diameter of about 2 Î¼m. For the eye to discern two images on the fovea

Marina CMI [18]

Answer:

The distance between the object is $l=0.0056\ cm$

Explanation:

The free body diagram of this setup is on the first uploaded image

From the question

The diameter of closely packed cones in the fovea of the eye is = $2 \mu m$

The distance of separation by one cone(not excited ) is $d = 4\mu m = 4*10^{-4}cm$

The distance between the two point-like object is l

The diameter of the eye is D = 2 cm

The distance of the two point-like object from the near point of the eye is A = 28 cm

From the diagram we see that the light from the two point-like object form a triangle of similar base l and d and height D and A

So for a triangle with similar base we have that

$\frac{l}{A} =\frac{d}{D}$

$\frac{l}{28} = \frac{4*10^{-4}}{2}$

making l the subject we have

$l = \frac{28 *4*10^{-4}}{2}$

$l=0.0056\ cm$

5 0

3 years ago

Read 2 more answers

A gold wire has a cross-sectional area of 1.0 cm^2 and a resistivity of 2.8 × 10^-8 Ω ∙ m at 20°C. How long would it have to be

Karo-lina-s [1.5K]

Answer:

Length, l = 3.57 meters

Explanation:

It is given that,

Area of cross-section of gold wire, $A=1\ cm^2=0.0001\ m^2$

Resistivity of gold wire, $\rho=2.8\times 10^{-8}\ \Omega-m$

Resistance, R = 0.001 ohms

Resistance in terms of length and area is given by :

$R=\rho \dfrac{l}{A}$

$l=\dfrac{RA}{\rho}$

$l=\dfrac{0.001\times 0.0001}{2.8\times 10^{-8}}$

l = 3.57 meters

So, the length of the wire is 3.57 meters. Hence, this is the required solution.

4 0

3 years ago