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ankoles [38]
3 years ago
5

What caused earths continents to drift apart?

Physics
2 answers:
soldier1979 [14.2K]3 years ago
6 0

Answer:

bada bop boop pow

Explanation:

miskamm [114]3 years ago
5 0

Answer:

The causes of continental drift are perfectly explained by the plate tectonic theory.  plate tectonic explanation<   Plate tectonics, theory dealing with the dynamics of Earth ’s outer shell—the lithosphere —that revolutionized Earth sciences by providing a uniform context for understanding mountain-building processes

Explanation:

MARK BRAINLIEST!!!!

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Determine the velocity (in m/s) of the object during the first six seconds. Include a numerical answer aceurate to the first dec
m_a_m_a [10]

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.66m/s

Explanation:

Using the formula V=D/T, we can take our distance, 9m, and put it over our time of 6 seconds.

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3 years ago
A uniform thin circular rubber band of mass M and spring constant k has an original radius R?
Gemiola [76]

Answer: Yes

Explanation:

A ruber band can be described by his mas, M, the spring constant K, and his rest radius, wich is the radius of the circular rubber band when there is no force applied to it, so yes, a uniform thin circular rubber band of mass M and spring constant k has an original radius R

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Define principal focus of concave mirror.Where should we place a candle in front of a concave mirror to get an enlarged,erect im
Mars2501 [29]

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Hope it helped u if yes mark me brainliest!

Tysm!

3 0
4 years ago
Which is the best evidence that continents that are now separated were once
Rasek [7]
I’d say It’s B since the plants and fossils are big indicators
3 0
3 years ago
Read 2 more answers
A block of mass 10 kg and measuring 250 mm on each edge is pulled up an inclined surface on which there is a film of SAE 10W-30
Ivan

Answer:

a) 2.53 * 10^-2 m/s

b) -4.78 * 10^-2 m/s

c)  1.21 * 10^-1 m/s

Explanation:

Given data :

Mass of block = 10 kg

Measuring 250mm on each side

a) calculate the speed  when a force of 75N is applied to pull block upwards

F = f + W sin∅ ( equation for applying the force of equilibrium condition in the x axis )  ----- ( 1 )

f ( friction force )=  ( 16400v * 6.25 *10^-2) =  1025 v

F ( force applied ) = 75

W ( weight of  block ) = 10 * 9.81 = 98.1 N

∅ = 30°

input values into equation 1

V = \frac{75- (98.1*sin30^{0}) }{1025} = 2.53 * 10^-2 m/s

b) Speed when no force is applied on the block

F = f + W sin∅

F = 0

f = 1025 V

W = 98.1 N

∅ = 30°

hence V = \frac{0 - (98.1*sin30^{0}) }{1025} =  - 4.78 * 10^-2 m/s

c) when a force is applied to push block down the incline

F = f + W sin∅ ----- ( 3 )

F = 75 N

f = 1025 V

W = 98.1 N

∅ = 30°

input values into equation 3 considering the fact that the weight of the block is acting in the opposite direction

75 = 1025 V - 98.1 ( sin 30° )

V = \frac{75+( 98.1*sin30^{0})  }{1025} = 1.21 * 10^-1 m/s

5 0
3 years ago
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