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3 years ago

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An object with more inertia is both harder to _ and to ___ ...?

1 answer:

Aleks [24]3 years ago

4 0

An object with more inertia is both harder to start and to stop. <span>The heavier (or more mass) of the object - harder to start & stop. For instance, a large rock vs. small rock. Large rock harder to get rolling & harder to stop as compared to smaller rocks. Hope this answers the question.</span>

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How can you model electromagnetic wave behavior?

eduard

Answer:

Wave and Particle model

Explanation:

A wave model best explains many of the behaviors, but a particle model best explains others.

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3 years ago

Read 2 more answers

A two-turn circular wire loop of radius 0.63 m lies in a plane perpendicular to a uniform magnetic field of magnitude 0.219 T. I

Basile [38]

Answer:

The magnitude of the average induced emf in the wire during this time is 9.533 V.

Explanation:

Given that,

Radius r= 0.63 m

Magnetic field B= 0.219 T

Time t= 0.0572 s

We need to calculate the average induce emf in the wire during this time

Using formula of induce emf

$E=-\dfrac{d\phi}{dt}$

$E=-B\dfrac{dA}{dt}$

$E=-B\dfrac{A_{2}-A_{1}}{dt}$

$E=B\dfrac{A_{1}-A_{2}}{dt}$ .....(I)

In reshaping of wire, circumstance must remain same.

We calculate the length when wire is in two loops

$l=2\times 2\pi\times r_{1}$

$l=2\times 2\pi\times 0.63$

$l=7.916\ m$

The length when wire is in one loop

$l=2\pi\times r_{2}$

$7.916=2\times \pi\times r_{2}$

$r_{2}=\dfrac{7.916}{2\times \pi}$

$r_{2}=1.259\ m$

We need to calculate the initial area

$A_{1}=N\times\pi\times r_{1}^2$

Put the value into the formula

$A_{1}=2\times3.14\times(0.63)^2$

$A_{1}=2.49\ m^2$

The final area is

$A_{2}=N\times\pi\times r_{2}^2$

$A_{2}=1\times\pi\times(1.259)^2$

$A_{2}=4.98\ m^2$

Put the value of initial area and final area in the equation (I)

$E=0.219\dfrac{2.49-4.98}{0.0572}$

$E=-9.533\ V$

Negative sign shows the direction of induced emf.

Hence, The magnitude of the average induced emf in the wire during this time is 9.533 V.

6 0

3 years ago

A 10 gram ball is rolling at 3 m/s. What is the energy the ball has?

s344n2d4d5 [400]

Answer:

K = 0.045 J

Explanation:

It is given that,

Mass of a ball, m = 10 g = 0.01 kg

Speed of the ball, v = 3 m/s

To find,

The energy of the ball.

Solution,

Due to the motion of the ball, it will have kinetic energy. It can be given by the formula as follows :

$K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 0.01\times 3^2\\\\K=0.045\ J$

So, the ball will have a kinetic energy of 0.045 J.

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3 years ago

Unpolarized light is passed through an optical filter that is oriented in the vertical direction.

VashaNatasha [74]

In order to solve this problem it is necessary to apply the concepts related to intensity and specifically described in Malus's law.

Malus's law warns that

$I = I_0 cos^2\theta$

Where,

$\theta=$ Angle between the analyzer axis and the polarization axis

$I_0 =$ Intensity of the light before passing through the polarizer

The intensity of the beam from the first polarizer is equal to the half of the initial intensity

$I = \frac{I_0}{2}$

Replacing with our the numerical values we get

$I = \frac{46}{2}$

$I = 23W/m^2$

Therefore the intensity of the light that emerges from the filter is $23W/m^2$

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3 years ago

Can a ratio be expressed as a percentage

cupoosta [38]

Yes, ratio can be expressed in percentage.

7 0

3 years ago