What's the time constant of a 10 H inductor and a 200 ohm resistor connected in series
1 answer:
<h3>Option B</h3><h3>The time constant of a 10 H inductor and a 200 ohm resistor connected in series is 50 millisecond</h3>
<em><u>Solution:</u></em>
Given that,
10 H inductor and a 200 ohm resistor connected in series
To find: time constant
<em><u>The time constant in seconds is given as:</u></em>
Where,
L is the inductance in henry and R is the resistance in ohms
Convert to millisecond
1 second = 1000 millisecond
0.05 second = 0.05 x 1000 = 50 millisecond
Thus time constant is 50 millisecond
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Answer:
or
.
Explanation:
<u>Given:</u>
- Charge on the particle at origin = Q.
- Mass of the moving charged particle,
- Charge on the moving charged particle,
- Distance of the moving charged particle from first at t = 0 time,
- Speed of the moving particle,
For the moving particle to circular motion, the electrostatic force between the two must be balanced by the centripetal force on the moving particle.
The electrostatic force on the moving particle due to the charge Q at origin is given by Coulomb's law as:
where, is the Coulomb's constant having value
The centripetal force on the moving particle due to particle at origin is given as:
For the two forces to be balanced,
A) 2.64t
B) 2.64h
C) 2.64D
Explanation:
A)
The motion of the athlete is equivalent to the motion of a projectile, which consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- A uniformly accelerated motion (constant acceleration) along the vertical direction
The time of flight of a projectile can be found from the equations of motion, and it is found to be
where
u is the initial speed
is the angle of projection
g is the acceleration due to gravity
In this problem, when the athlete is on the Earth, the time of flight is .
When she is on Mars, the acceleration due to gravity is:
where g is the acceleration due to gravity on Earth. Therefore, the time of flight on Mars will be:
B)
The maximum height reached by a projectile can be also found using the equations of motion, and it is given by
where
u is the initial speed
is the angle of projection
g is the acceleration due to gravity
In this problem, when the athlete is on the Earth, the maximum height is .
When she is on Mars, the acceleration due to gravity is:
where g is the acceleration due to gravity on Earth. So, the maximum height reached on Mars will be:
C)
The horizontal distance covered by a projectile is also found from the equations of motion, and it is given by
where:
u is the initial speed
is the angle of projection
g is the acceleration due to gravity
In this problem, when the athlete is on the Earth, the horizontal distance covered is D.
When she is on Mars, the acceleration due to gravity is:
where g is the acceleration due to gravity on Earth. Therefore, the horizontal distance reached on Mars will be: