1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aliina [53]
3 years ago
5

Two objects are in freefall. Object A experiences a gravitational force of

Physics
1 answer:
Vlad1618 [11]3 years ago
3 0

<u>Answer:</u>

Both the objects A and B will have the same acceleration.

<u>Explanation :</u>

The objects will have the same acceleration as both are under free fall condition. When objects are under the free fall condition, the only force that acts on the object is its weight.

Weight is the force acting on a body of some mass, and the formula for finding the weight of a body is- Weight = mass × acceleration due to gravity(g).

Therefore, here the different weight is due to the difference masses of both bodies, and not due to the different acceleration values.

You might be interested in
A 15 n net force is used to move a 5kg box. What is the resulting acceleration?
Mamont248 [21]

Answer:3 m/s

Explanation:

8 0
3 years ago
Answer this question, please​
pashok25 [27]

Answer:

the correct answer is the 60

+ 20 + 60 \gamma  \beta

3 0
3 years ago
Copper and aluminum are being considered for a high-voltage transmission line that must carry a current of 60.7 A. The resistanc
lisov135 [29]

Answer:

a) The magnitude JJ of the current density for a copper cable is 5.91 × 10⁵A.m⁻²

b)The mass per unit length \lambdaλ for a copper cable is 0.757kg/m

c)The magnitude J of the current density for an aluminum cable is 3.5 × 10⁵A/m²

d)The mass per unit length \lambdaλ for an aluminum cable is 0.380kg/m

Explanation:

The expression for electric field of conductor is,

E =  \frac{V}{L}

The general equation of voltage is,

V = iR

The expression for current density in term of electric field is,

J = \frac{E}{p}

Substitute (V/L)  for E in the above equation of current density.

J = \frac{V}{pL} ------(1)

Substitute iR for V in equation (1)

J = \frac{iR}{pL} ------(2)

Substitute 1.69 × 10⁸ Ω .m for p

50A for i

0.200Ω.km⁻¹ for (R/L) in eqn (2)

J = \frac{(50) (0.200\times 10^-^3) }{1.69 \times 10^-^8 } \\\\= 5.91 \times 10^5A.m^-^2

The magnitude JJ of the current density for a copper cable is 5.91 × 10⁵A.m⁻²

b) The expression for resistivity of the conductor is,

p = \frac{RA}{L}

A = \frac{pL}{R}

The expression for mass density of copper is,

m = dV

where, V is the density of the copper.

Substitute AL for V in equation of the mass density of copper.

m=d(AL)

m/L = dA

λ is use for (m/L)

substitute,

pL/R for A  and λ is use for (m/L) in the eqn above

\lambda = d\frac{p}{\frac{R}{L} } ------(3)

Substitute 0.200Ω.km⁻¹ for (R/L)

8960kgm⁻³  for d and 1.69 × 10⁸ Ω .m

\lambda = (8960) \frac{(1.69 \times 10^-^8 }{0.200\times 10^-^3} \\\\= 0.757kg.m^-^1

c) Using the equation (2) current density for aluminum cable is,

J = \frac{iR}{pL}

p is the resistivity of the aluminum cable.

Substitute 2.82 × 10⁻⁸Ω.m for p ,

50A for i and 0.200Ω.km⁻¹ for (R/L)

J = \frac{(50)(0.200\times10^-^3) }{2.89\times 10^-^8} \\\\= 3.5 \times10^5A/m^2

The magnitude J of the current density for an aluminum cable is 3.5 × 10⁵A/m²

d) Using the equation (3) mass per unit length for aluminum cable is,

\lambda = d\frac{p}{\frac{R}{L} }

p is the resistivity and is the density of the aluminum cable.

Substitute 0.200Ω.km⁻¹ for (R/L), 2700 for d and 2.82 × 10⁻⁸Ω.m for p

\lambda = (2700) \frac{(2.82 \times 10^-^8) }{(0.200 \times 10^-^3) } \\\\= 0.380kg/m

The mass per unit length \lambdaλ for an aluminum cable is 0.380kg/m

7 0
3 years ago
Read 2 more answers
Can somebody tell me what time is it
kodGreya [7K]

Answer:

8:21am

Explanation:

I hate stupid school

5 0
2 years ago
Read 2 more answers
Express the distance between the moon and earth in meters with a meter prefix (km).
tankabanditka [31]

Answer;

= 3.86 × 10^8 Meters

Explanation;

-The distance between the Earth and the moon is 386000 km

But; 1 km = 1000 m

Therefore; 386000 km will be equivalent to;

= 386000 × 1000

= 386000000 m

= 3.86 × 10^8 meters

3 0
2 years ago
Read 2 more answers
Other questions:
  • Suppose two waves collide, and the temporary combined wave that results is smaller than the original waves. what term best descr
    14·1 answer
  • The drawing shows an electron entering the lower left side of a parallel plate capacitor and exiting at the upper right side. Th
    9·1 answer
  • A device for increasing or decreasing voltage through electromagnetic induction.
    13·1 answer
  • Consider the incomplete equation below mc020-1.jpg If this equation was completed, which statement would it best support? Nuclea
    11·2 answers
  • An element's atomic number is 7. How many electrons would an atom of this element have?
    12·1 answer
  • Sully uses a battery and a coil of wire to create an electromagnet. Using the same materials, if he wants to increase the streng
    9·2 answers
  • Explain how an increase or decrease in the permeability (i.e. opening or closing channels permeable) to K+, Na+, Ca2+, or Cl- wo
    11·1 answer
  • What did the protoplanets become?
    5·2 answers
  • Aunt Mary needs to hang a picture in her bedroom. She uses a hammer to drive the nail into the wall. Find the force exerted by t
    11·1 answer
  • Resolve the weight of the box to find the component of the weight acting parallel to the slope.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!