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inysia [295]
3 years ago
8

What is the new acceleration (in m/s/s)?

Physics
1 answer:
Delicious77 [7]3 years ago
8 0

The new acceleration is 108 m/s^2

Explanation:

We can answer this problem by applying Newton's second law, which states that:

F=ma

where

F is the net force on an object

m is the mass of the object

a is its acceleration

The equation can be rewritten as

a=\frac{F}{m}

In this problem, the initial acceleration is

a=18.0 m/s^2

Later:

- The net force is tripled: F'=3F

- The mass is halved: m'=\frac{m}{2}

Therefore, the new acceleration is:

a'=\frac{F'}{m'}=\frac{3F}{m/2}=6\frac{F}{m}=6a

which means that the new acceleration is 6 times the original acceleration, therefore

a'=6(18)=108 m/s^2

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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A car goes round a curve of radius 48m, the road is banked at an angle of 15 with the horizontal,at what maximum speed may the c
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Substitute and solve for v:

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Plug in values:

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Rounded to 2 significant figures, the maximum speed is 11 m/s.

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The resultant of two vectors is simply the vector sum of the vectors. There are a handful of ways to present the resultant factor; the notation that shows the vector magnitude and direction is called the polar vector notation. An example of a vector presented in polar vector notation is

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Answer and Explanation:

Let's first present the vectors in rectangular vector notation.

For the vector →u of magnitude 20 and direction 0∘ to the horizontal axis, the vector is →u=^i20.

For the vector →v

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The resultant vector →w is the vector sum of the vectors, i.e.

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The magnitude of the vector is about 53 units in the direction 41-degrees above the horizontal axis.

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