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svlad2 [7]
3 years ago
15

A certain liquid has a density of 0.70g/m. Find the mass of 6.4L o this liquid

Chemistry
1 answer:
neonofarm [45]3 years ago
5 0

The mass of the liquid is 4.8 kg.

6.4 L = 6400 mL

Mass = 6400 mL × (0.70 g/1 mL) = 4500 g = 4.8 kg

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How do properties of waves affect light and sound
Iteru [2.4K]

Answer:

Explanation:

Both light and sound can be described in terms of wave forms with physical characteristics like amplitude, wavelength, and timbre. Wavelength and frequency are inversely related so that longer waves have lower frequencies, and shorter waves have higher frequencies.

4 0
3 years ago
Water has a high specific heat because: Select one: a. it is a poor insulator b. hydrogen bonds must be broken to raise its temp
Crank
<h2>The required "option is b) hydrogen bonds must be broken to raise its temperature.</h2>

Explanation:

  • Water has high specific heat due to hydrogen bonds present in it.
  • The Ionisation of water does not affect the specific heat of the water.
  • On decreasing the temperature, there is the formation of bonds hence option (d) is wrong.
  • On increasing the temperature, there is the breaking of bonds hence option (b) is correct.
3 0
3 years ago
Please help i have untill tomrow 2SO2(g) + O2(g) ----&gt; 2SO3(g)
siniylev [52]

Answer:  mmmmmm asking for mrs.howard work I see lol good luck grace

Explanation:

8 0
3 years ago
1. How many molecules are found in 13.7 moles of CuNO3? <br><br> Please explain step by step
Gennadij [26K]

Answer:

1 moles

Explanation:

The answer is 0.0011897028836018. We assume you are converting between moles CuNo3 and gram. You can view more details on each measurement unit: molecular weight of CuNo3 or grams The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CuNo3, or 840.546 grams.

7 0
3 years ago
50.0 ml of 0.010m naoh was titrated with 0.50m hcl using a dropper pipet. if the average drop from the pipet has a volume of 0.0
creativ13 [48]

25 drops of acid is required to neutralize the 50.0 ml of 0.010m of NaOH in the experiment.

The equation of the reaction is;

NaOH(aq) + HCl(aq) ---------> NaCl(aq) + H2O(l)

We can use the titration formula;

CAVA/CBVB = NA/NB

CA= concentration of acid

VA = volume of acid

CB = concentration of base

VB = volume of base

NA = number of moles of acid

NB = number of moles of base

CB = 0.010 M

VB = 50.0 ml

CA = 0.50 M

VA = ?

NA = 1

NB = 1

Substituting values;

CAVANB = CBVBNA

VA =  0.010 ×  50.0 × 1/ 0.50 × 1

VA = 1 ml

Since the total volume of acid used is 1 ml and each drop contains 0.040 ml

The number of drops required is 1ml/0.040 ml = 25 drops

Learn more: brainly.com/question/1527403

4 0
3 years ago
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