1. Developing renewable energy technology
- Efficient energy storage and smarter grids .
- renewable and rechargeable batteries and fuel cell
2. Saving endangered wildlife
-smart collars for endangered species and reducing human - animal conflict
-Gene sequencing for detecting and researching on deadly animal diseases.
3. Adopting a smarter lifestyle
- smart homes that promote energy saving and green - living .
- electric cars which are three times more conventional vehicles .
Hope this helps :)
answer:
yes
explanation:
At a separation of the surface of Earth (r=6400km) gravity wants pull the test mass closer and closer. ... So the work done by gravity is NEGATIVE. The gravitational potential energy is negative because us trying to do the opposite of what gravity wants needs positive energy.
Answer:
Parallel universe, or alternate reality, is a hypothetical self-contained plane of existence, co-existing with one's own
Answer:1.084
Explanation:
Given
mass of Pendulum M=10 kg
mass of bullet m=5.5 gm
velocity of bullet u
After collision let say velocity is v
conserving momentum we get


Conserving Energy for Pendulum
Kinetic Energy=Potential Energy

here
from diagram
therefore

initial velocity in terms of v

For first case 

for second case 

Therefore 


i.e.