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Licemer1 [7]
3 years ago
15

How much force is need to accelerate a skier that is 66kg at a rate of 2 m/s2?

Physics
1 answer:
lubasha [3.4K]3 years ago
8 0

Answer:

132 N

Explanation:

newton's second law states that force = mass * acceleration

F = ma

plug in 66 kg for mass and 2 m/s^2 for acceleration

F = 66 * 2

F = 132 N

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What pressure in units of torr is equal to 1.14 atm of pressure?
likoan [24]
1 atm / 760torr or 760torr / atm -->
1.14atm / 1 × 760torr / atm = 1.14×760torr = 866.4torr
7 0
4 years ago
The international Space Station (ISS) orbits the Earth once every 90 mins at an altitude of 409 km. How high would it have to be
Oksi-84 [34.3K]

It would have to be 36,719 Km high in order to be to be in geosynchronous orbit.

To find the answer, we need to know about the third law of Kepler.

<h3>What's the Kepler's third law?</h3>
  • It states that the square of the time period of orbiting planet or satellite is directly proportional to the cube of the radius of the orbit.
  • Mathematically, T²∝a³
<h3>What's the radius of geosynchronous orbit, if the time period and altitude of ISS are 90 minutes and 409 km respectively?</h3>
  • The time period of geosynchronous orbit is 24 hours or 1440 minutes.
  • As the Earth's radius is 6371 Km, so radius of the ISS orbit= 6371km + 409 km = 6780km.
  • If T1 and T2 are time period of geosynchronous orbit and ISS orbit respectively, a1 and a2 are radius of geosynchronous orbit and ISS orbit, as per third law of Kepler, (T1/T2)² = (a1/a2)³
  • a1= (T1/T2)⅔×a2

           = (1440/90)⅔×6780

           = 43,090 km

  • Altitude of geosynchronous orbit = 43,090 - 6371= 36,719 km

Thus, we can conclude that the altitude of geosynchronous orbit is 36,719km.

Learn more about the Kepler's third law here:

brainly.com/question/16705471

#SPJ4

   

6 0
2 years ago
Davien and Jackson are headed to a beach that is 50km from school. At noon, Davien leaves his house that is 10 km closer to the
snow_tiger [21]

Distance between Davien's school and beach, D = 50 km.

Also, Davian's house is 10 km closer to the beach than the school.

So, distance between Davien's house and beach, d = 40 km.

Speed of Davian, s = 40 km/h.

Now, time taken is given by :

t =\dfrac{Distance}{Speed}\\\\t=\dfrac{40}{40}=1\ hour

Therefore, Davien reach the beach at 1 : 30 P.M .

Hence, this is the required solution.

5 0
3 years ago
A 72 kg sled Is pulled forward from rest by a snowmobile and accelerates at 2 m/s squared forward for five seconds. The force of
Inga [223]
So first make a force diagram. I would label forward forces + and backward forces -. Essentially, the drag force is equal to the Ft (force of tension) + Ff (force of friction on snowmobile - driver system). The force of Friction is equal to mu * Fn. We can find mu through the force of friction acting on the sled. 120 N = mu * Fn (equal to m * g of sled). mu of the Ice is equal to 0.167. So, 540 N = Ft + 0.167 * 4500 N. Ft = -211.5 N. <u>Ft is acting in the backwards direction at a magnitude of 211.5 N</u>
3 0
4 years ago
You and your lab partner, Mel, are engrossed in a chemistry activity using beans to compute the average atomic mass of an elemen
Vikentia [17]

Answer:

C:

Explanation:

either C or A but A seems unlikely after multiple attempts. Although the question doesn't make it clear whether the balance is electric either way it could be wrong in someway and seems to be the most likely.

5 0
3 years ago
Read 2 more answers
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