For this case we have that the final speed is given by:
Where,
a: acceleration
vo: initial speed
t: time
Clearing the time we have:
Substituting values we have:
it takes 4.375 s for the car to stop
Hi there!
Since the object is being pulled at a constant velocity, the forces must be balanced.
Since there is no movement vertically, we must take into account the horizontal forces. We can also assume a positive acceleration to be in the direction of motion.
The acceleration and force due to gravity on an incline is:
a = gsinФ
F = MgsinФ
∑F = -MgsinФ + T
Since it is getting pulled at a constant velocity, ∑F = 0. So:
0 = -MgsinФ + T
MgsinФ = T
Solve for T by plugging in values. Let g = 10 m/s²
T = (120)(10)sin(27) ≈ 545 N
Answer:
5*10^25 atoms of carbon
Explanation:
<u>Check from the periodic table:</u>
M(carbon) = 12.01 g/mol
<u>Convert kg into g:</u>
1 kg = 1000 g
<u>Calculate the number of moles of carbon:</u>
n(carbon) = (1000 g) ÷ (12.01 g/mol) = 83.26 mol
<u>Convert moles into number of particles:</u>
#(carbon) = n × NA = 83.26 mol × 6*10^23
= 5*10^25 particles
<em>N</em><em>o</em><em>t</em><em>e</em><em>:</em><em> </em><em>NA represents the Avogadro's Number, which has the value 6.02*10^23 particles/mol</em><em>.</em>
Answer:
Explanation:
The degree of hotness and coldness of the body is called temperature.